PHP inhertience方法引用

Question

<?php
class A {
    private function foo() {
        echo "baf!<br/>";
    }
    public function test() {
        $this->foo();

    }
}


class C extends A {
    private function foo() {
        echo "bar!<br/>";
    }

}

$c = new C();
$c->test();  //Prints baf!
?> 

怎么做c->test()打印吧!？我期待它foo()会被覆盖C并打印吧!有人可以向我解释一下吗？

Answer 1

通过使两种方法都受到保护,您将获得所需的结果; 的原因是内A::test()它只能解决$this->foo()对A::foo()因的private知名度.见可见性.

class A {
    protected function foo() {
        echo "baf!<br/>";
    }
    public function test() {
        $this->foo();

    }
}


class C extends A {
    protected function foo() {
        echo "bar!<br/>";
    }

}

$c = new C();
$c->test();  //Prints bar!