Rap*_*ael 3 c# linq generics lambda
我有以下课程:
public class MyClass<T> where T : class
{
public void Method1<TResult>(T obj, Expression<Func<T, TResult>> expression)
{
//Do some work here...
}
public void Method2<TResult>(T obj, Expression<Func<T, TResult>> expression1, Expression<Func<T, TResult>> expression2)
{
//Do some work here...
}
}
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我可以像这样调用Method1:
MyClass<SomeOtherClass> myObject = new MyClass<SomeOtherClass>();
myObject.Method1(someObject, x => x.SomeProperty);
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但是当我尝试调用Method2时:
MyClass<SomeOtherClass> myObject = new MyClass<SomeOtherClass>();
myObject.Method2(someObject, x => x.SomeProperty, x => x.SomeOtherProperty);
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我得到以下编译时错误:
Error 1 The type arguments for method 'MyClass.Method2<SomeOtherClass>.Method2<TResult>(SomeOtherClass obj, System.Linq.Expressions.Expression<System.Func<SomeOtherClass,TResult>>, System.Linq.Expressions.Expression<System.Func<SomeOtherClass,TResult>>)' cannot be inferred from the usage. Try specifying the type arguments explicitly.
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我怎样才能创建一个接受两个lambdas的方法并按照我的意图调用它?
做SomeProperty和SomeOtherProperty有相同的类型?如果没有,那就是你的问题,因为你正在使用一个TResult类型参数.
解决方案只是使用两个类型参数:
public void Method2<TResult1, TResult2>(T obj, Expression<Func<T, TResult1>> expression1, Expression<Func<T, TResult2>> expression2)
{
//Do some work here...
}
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