如何在URL中传递Javascript变量？AJAX

Question

我试图在我使用的网址中传递accesstoken和pageid的值.任何想法如何正确地做到这一点？

<script type="text/javascript">   
function makeUrl() {
    var accesstoken = "12345679|bababashahahhahauauuaua";
    var pageid =  "<?php echo $page_id;?>";
 $.ajax(
  {
    url: 'https://graph.facebook.com/?pageid/?access_token='+pageid+accesstoken,
 statusCode: {......

Answer 1

更改

url: 'https://graph.facebook.com/?pageid/?access_token='+pageid+accesstoken,

至

url: 'https://graph.facebook.com/?pageid='+pageid+'&access_token='+accesstoken,