Ras*_*oov 6 c# recursion dictionary traversal
我想将嵌套类转换为漂亮的键/值字典,并保留每个属性的类名和嵌套路径,以便以后轻松搜索.
这是我的示例类:
var agreement = new Agreement
{
ID = 101,
Description = "Convert to dictionary",
Customer = new Customer
{
FirstName = "John",
LastName = "Smith",
Age = 30,
Address = new List<Address>()
{
new Address
{
Name = "Los Angeles 1",
ZipCode = 25437
},
new Address
{
Name = "New York 25",
ZipCode = 25441
}
}
}
};
Run Code Online (Sandbox Code Playgroud)
这是我在字典中预期的键/值输出:
KEY VALUE
Agreement.ID: 101
Agreement.Description: Convert to dictionary
Agreement.Customer.FirstName: John
Agreement.Customer.LastName: Smith
Agreement.Customer.Age: 30
Agreement.Customer.Address[0].Name: Los Angeles 1
Agreement.Customer.Address[0].ZipCode: 25437
Agreement.Customer.Address[1].Name: New York 25
Agreement.Customer.Address[1].ZipCode: 25441
Run Code Online (Sandbox Code Playgroud)
任何人都知道如何实现这一目标?
(道歉,我没有时间来测试这个.)
您可以使用反射和递归编写解决方案.下面这样的东西.
您将需要添加空检查和其他退出情况,否则您将很快进入infinate循环. 这只是为了让你开始.
public Dictionary<string, string> MapToDictionary(object source, string name)
{
var dictionary = new Dictionary<string, string>();
MapToDictionaryInternal(dictionary, source, name);
return dictionary;
}
private void MapToDictionaryInternal(
Dictionary<string, string> dictionary, object source, string name)
{
var properties = source.GetType().GetProperties();
foreach(var p in properties)
{
var key = name + "." + p.Name;
object value = p.GetValue(source, null);
Type valueType = value.GetType();
if (valueType.IsPrimitive || valueType == typeof (String))
{
dictionary[key] = value.ToString();
}
else if (value is IEnumerable)
{
var i = 0;
foreach (object o in (IEnumerable) value)
{
MapToDictionaryInternal(dictionary, o, key + "[" + i + "]");
i++;
}
}
else
{
MapToDictionaryInternal(dictionary, value, key);
}
}
}
Run Code Online (Sandbox Code Playgroud)
像这样称呼它:
Dictionary<string, string> dictionary2 = MapToDictionary(agreement, "Agreement");
Run Code Online (Sandbox Code Playgroud)