C++:宽字符输出不正确？

Question

我的代码基本上是这样的:

wstring japan = L"??";
wstring message = L"Welcome! Japan is ";

message += japan;

wprintf(message.c_str());

我希望使用宽字符串,但我不知道它们是如何输出的,所以我使用了wprintf.当我运行如下的东西时:

./widestr | hexdump

十六进制代码点创建了这个:

65 57 63 6c 6d 6f 21 65 4a 20 70 61 6e 61 69 20 20 73 3f 3f
e  W  c  l  m  o  !  e  J     p  a  n  a  i        s  ?  ?

为什么他们都按顺序跳了？我的意思是如果wprintf是错的,我仍然不明白为什么它会以这样一个特定的混乱顺序输出!

编辑:endianness还是什么？他们似乎旋转每两个字符.呵呵.

编辑2:我尝试使用wcout,但它输出完全相同的十六进制代码点.奇怪的!

Answer 1

You need to define locale

    #include <stdio.h>
    #include <string>
    #include <locale>
    #include <iostream>

    using namespace std;

    int main()
    {

            std::locale::global(std::locale(""));
            wstring japan = L"??";
            wstring message = L"Welcome! Japan is ";

            message += japan;

            wprintf(message.c_str());
            wcout << message << endl;
    }

Works as expected (i.e. convert wide string to narrow UTF-8 and print it).

When you define global locale to "" - you set system locale (and if it is UTF-8 it would be printed out as UTF-8 - i.e. wstring will be converted)

Edit: forget what I said about sync_with_stdio -- this is not correct, they are synchronized by default. Not needed.