rya*_*ack 10 javascript maps openlayers-3
我无法找到从选择事件中的某个要素转到可能是其中一部分而无需遍历所有地图图层的所有要素,或者在创建时在每个要素中存储人工图层ID的图层.这是不可能的吗?
ol.js 3.7.0 ol.interaction.Selection - > click - > callback(event){event.selected [0]}
在我的应用程序的另一部分,我想从功能到图层来确定功能上使用的样式,特别是它是否可见.
ol.Feature.getStyle()|| ol.Feature - >(图层?) - > getStyle()
Jon*_*ker 11
您可以尝试使用过滤功能:
var select = new ol.interaction.Select({
condition: ...,
filter: function(feature, layer){
console.info(feature);
console.info(layer.get('name'));
}
});
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UPDATE
我想出了这个原型方法,它完成了这项工作:
http://jsfiddle.net/jonataswalker/r242y7ke/
/**
* This is a workaround.
* Returns the associated layer.
* @param {ol.Map} map.
* @return {ol.layer.Vector} Layer.
*/
ol.Feature.prototype.getLayer = function(map) {
var this_ = this, layer_, layersToLookFor = [];
/**
* Populates array layersToLookFor with only
* layers that have features
*/
var check = function(layer){
var source = layer.getSource();
if(source instanceof ol.source.Vector){
var features = source.getFeatures();
if(features.length > 0){
layersToLookFor.push({
layer: layer,
features: features
});
}
}
};
//loop through map layers
map.getLayers().forEach(function(layer){
if (layer instanceof ol.layer.Group) {
layer.getLayers().forEach(check);
} else {
check(layer);
}
});
layersToLookFor.forEach(function(obj){
var found = obj.features.some(function(feature){
return this_ === feature;
});
if(found){
//this is the layer we want
layer_ = obj.layer;
}
});
return layer_;
};
select.on('select', function(evt){
var feature = evt.selected[0];
if(feature){
var layer = feature.getLayer(map);
console.info(layer.getStyle());
console.info(layer.get('name'));
}
});
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小智 5
在 OL 5.3.0 中,Select 交互对象具有getLayer()函数来获取最后选择的要素的关联图层。例子:
let selectClick = new Select({});
map.addInteraction(selectClick);
selectClick.on('select', function(e) {
let featureSelected = e.selected[0];
let layer = selectClick.getLayer(featureSelected);
console.log(layer); // here you have the selected layer
});
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