the*_*ker 8 java hibernate jpa jpql
我有四个参与查询的实体,我遇到了一些麻烦.关系如下:(Exchange----*Contract*----*Combo----*Trade简化)实体如下:
@Entity
public class Exchange implements Serializable {
@Id(name="EXCHANGE_ID")
private long exchangeId;
@Column
private String exchangeShortName;
}
@Entity
public class Contract implements Serializable {
@Id
private long contractId;
@Column
private String contractName;
@ManyToOne
@JoinColumn(name="EXCHANGE_ID")
private Exchange exchange;
@ManyToMany
@JoinTable(name="CONTRACT_COMBO",
joinColumns = { @JoinColumn(name="CONTRACT_ID") },
inverseJoinColumns = {@JoinColumn(name="COMBO_ID")})
private Set<Combo> combos;
@Column(name = "ACTIVE_FLAG")
private String activeFlag;
}
@Entity
public class Combo implements Serializable {
@Id
@Column(name="COMBO_ID")
private Integer id;
@ManyToMany
@JoinTable(name="CONTRACT_COMBO",
joinColumns = { @JoinColumn(name="COMBO_ID") },
inverseJoinColumns = {@JoinColumn(name="CONTRACT_ID")})
private Set<Contract> legs;
@OneToMany(mappedBy = "combo")
private Set<Trade> trades;
}
@Entity
public class Trade implements Serializable {
@Id
@Column(name="TRADE_ID")
private long tradeId;
@Column(name="REFERENCE")
private String reference;
@ManyToOne
@JoinColumn(name="COMBO_ID")
private Combo combo;
}
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我想得到一个特定交易所的所有交易清单,我无法与之合作MEMBER OF.任何帮助,将不胜感激.
Mac*_*uch 10
试试这个
select distinct t
from Trade t
join t.combo c
join c.legs l
join l.exchange e
where e.exchangeShortName = 'whatever'
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