Python 3.4 plistlib不起作用（str vs字节错误）

Question

因此，我开始了一个新的玩具项目，并决定我将首次使用Python 3 ...

In [1]: import plistlib

In [2]: with open("/Volumes/Thunderbay/CURRENT/Music/iTunes/iTunes Library.xml") as itl:
    library = plistlib.load(itl)
   ...:
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-3-6459a022cb71> in <module>()
      1 with open("/Volumes/Thunderbay/CURRENT/Music/iTunes/iTunes Library.xml") as itl:
----> 2     library = plistlib.load(itl)
      3

/usr/local/Cellar/python3/3.4.3_1/Frameworks/Python.framework/Versions/3.4/lib/python3.4/plistlib.py in load(fp, fmt, use_builtin_types, dict_type)
    984         fp.seek(0)
    985         for info in _FORMATS.values():
--> 986             if info['detect'](header):
    987                 P = info['parser']
    988                 break

/usr/local/Cellar/python3/3.4.3_1/Frameworks/Python.framework/Versions/3.4/lib/python3.4/plistlib.py in _is_fmt_xml(header)
    556
    557     for pfx in prefixes:
--> 558         if header.startswith(pfx):
    559             return True
    560

TypeError: startswith first arg must be str or a tuple of str, not bytes

好的，让我们给它一个提示：

In [3]: with open("/Volumes/Thunderbay/CURRENT/Music/iTunes/iTunes Library.xml") as itl:
    library = plistlib.load(itl, fmt=plistlib.FMT_XML)
   ...:
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-4-ef5f06b44ec2> in <module>()
      1 with open("/Volumes/Thunderbay/CURRENT/Music/iTunes/iTunes Library.xml") as itl:
----> 2     library = plistlib.load(itl, fmt=plistlib.FMT_XML)
      3

/usr/local/Cellar/python3/3.4.3_1/Frameworks/Python.framework/Versions/3.4/lib/python3.4/plistlib.py in load(fp, fmt, use_builtin_types, dict_type)
    995
    996     p = P(use_builtin_types=use_builtin_types, dict_type=dict_type)
--> 997     return p.parse(fp)
    998
    999

/usr/local/Cellar/python3/3.4.3_1/Frameworks/Python.framework/Versions/3.4/lib/python3.4/plistlib.py in parse(self, fileobj)
    323         self.parser.EndElementHandler = self.handle_end_element
    324         self.parser.CharacterDataHandler = self.handle_data
--> 325         self.parser.ParseFile(fileobj)
    326         return self.root
    327

TypeError: read() did not return a bytes object (type=str)

plistlib是在标准库中，但是从上面的问题中我感觉到它实际上尚未转换为Python 3？

我想知道我决定在2.7上尝试Python 3的决定是否只是证明受虐狂和毫无意义...

哦，是的，实际的问题是：是否可以plistlib在Python 3.4.3中打开XML plist文件？

我肯定在这里可能遗漏了一些东西……只是注意到Py2版本plistlib（有效！）具有不同的界面，所以实际上有人修改了库的代码以包含在Py3中...

Answer 1

感谢@J Presper Eckert给我一个关于寻找的线索...

然后，我找到了这篇文章：http :
//python-notes.curiousefficiency.org/en/latest/python3/text_file_processing.html#the-binary-option

这表明答案很简单，就是以二进制模式打开文件，尝试了一下就可以了！

with open("/Volumes/Thunderbay/CURRENT/Music/iTunes/iTunes Library.xml", 'rb') as itl:
    library = plistlib.load(itl)