如何在Python中获取JSON的字段特定值？

Question

我目前正在研究从 json 中提取字段，然后对其进行一些利用。因此我有面部参数，并且我想存储每个字段的值。我正在尝试从面部 JSON 中获取性别值：JSON 如下：

{
  "face": [
    {
      "attribute": {
        "age": {
          "range": 5,
          "value": 24
        },
        "gender": {
          "confidence": 99.9999,
          "value": "Female"
        },
        "glass": {
          "confidence": 99.4157,
          "value": "None"
        },
        "pose": {
          "pitch_angle": {
            "value": 0.000001
          },
          "roll_angle": {
            "value": 0.650337
          },
          "yaw_angle": {
            "value": -0.42409
          }
        },
        "race": {
          "confidence": 98.058,
          "value": "Asian"
        },
        "smiling": {
          "value": 3.78394
        }
      },
      "face_id": "42245f24335ad21ea7c54f2db96a09b3",
      "position": {
        "center": {
          "x": 50.121951,
          "y": 35.97561
        },
        "eye_left": {
          "x": 43.465122,
          "y": 30.670488
        },
        "eye_right": {
          "x": 56.80878,
          "y": 30.821951
        },
        "height": 27.560976,
        "mouth_left": {
          "x": 45.649512,
          "y": 45.041707
        },
        "mouth_right": {
          "x": 55.134878,
          "y": 44.858049
        },
        "nose": {
          "x": 50.183415,
          "y": 38.410732
        },
        "width": 27.560976
      },
      "tag": ""
    }
  ],
  "img_height": 410,
  "img_id": "1e3007cb3d6cfbaed3a1b4135524ed25",
  "img_width": 410,
  "session_id": "76ec7f99a471418fa8862a2138cc589d",
  "url": "http://www.faceplusplus.com/wp-content/themes/faceplusplus/assets/img/demo/1.jpg?v=2"
}

我想从上面的 json 中提取“女性”。为此，我使用了这个：

 import urllib2
 import io, json
 from bs4 import BeautifulSoup
 data = soup #soup has all the data json
 with open('data.json', 'w') as outfile:
     json.dump(data, outfile, sort_keys = True, indent = 4, ensure_ascii=False)
 #content = json.loads(soup)
 jsonFile = open('data.json', 'r')
 values = json.load(jsonFile)
 jsonFile.close()
 gender = soup['face'][0]['gender']['value']
 print gender

我的代码哪里不正确？

Answer 1

根据您的 json 示例，gender位于内部attribute，因此您需要将其访问为 -

gender = soup['face'][0]['attribute']['gender']['value']

另外，似乎values是读回的 json （字典），所以你可能想使用它来访问它values，尽管我不确定你想要实现什么，所以我不能肯定地说。