在perl中的子例程之后,哈希键值更改为数组引用

Question

我在同一个哈希上创建子程序外部和内部的键.但是,在子例程之后,调用子例程之前创建的键中的值现在被解释为数组引用.

#!/usr/bin/perl
use module;
use strict;
use warnings;
my %hash;
my $count = 0;

my @array = ("a", "b", "c", "d");

for my $letter (@array) {
    $hash{$letter} = $count;
    $count++;
}

# need "\" to pass in hash otherwise changes
# will get lost outside of subroutine
foreach my $x (sort keys %hash) {
    print "first $hash{$x}\n";
}

module::add_ten(\%hash);

foreach my $p (sort keys %hash) {
    # $hash{$p} is printing array references, but before it was
    # printing the value I desired.  What did the subroutine do?
    print "second $hash{$p} $hash{$p}->{ten}\n";
}

这是带有子程序的模块

package module;

sub add_ten {
my $count = 10;
    # this passes the full array as reference
    my ($hash_ref) = @_; # $hash_ref is actually %hash (yes, the % is not a typo)
    my @keys = keys $hash_ref;
    foreach my $ltr (sort keys $hash_ref) {
        $hash_ref->{$ltr} = { ten => $count };
        $count++;
    }
}
1;

这是输出:

first 0
first 1
first 2
first 3
second HASH(0x7ff0c3049c50) 10
second HASH(0x7ff0c3049bc0) 11
second HASH(0x7ff0c3049b90) 12
second HASH(0x7ff0c3049b60) 13

我期待输出为:

first 0
first 1
first 2
first 3
second 0 10
second 1 11
second 2 12
second 3 13

我修改了我的模块:

package module;

sub add_ten {
    my $count = 10;
    # this passes the full array as reference
    my ($hash_ref) = @_; # $hash_ref is actually %hash (yes, the % is not a typo)
    my @keys = keys $hash_ref;
    foreach my $ltr (sort keys $hash_ref) {
        $hash_ref->{$ltr}{ten}=$count;
        $count++;
    }
}
1;

和主脚本(需要注释use strict以使其工作):

#!/usr/bin/perl
use module;
#use strict;
use warnings;
my %hash;
my $count = 0;

my @array = ("a", "b", "c", "d");

for my $letter (@array) {
    $hash{$letter} = $count;
    $count++;
}

# need "\" to pass in hash otherwise changes
# will get lost outside of subroutine
foreach my $x (sort keys %hash) {
    print "first $hash{$x}\n";
}

module::add_ten(\%hash);

foreach my $p (sort keys %hash) {
    print "second $hash{$p} $hash{$p}{ten}\n";
}

但这正是我想要达到的目标.

Answer 1

$hash_ref是一个引用%hash,因此当您更改引用的哈希元素的值时$hash_ref,您将更改哈希值%hash.

这意味着当你这样做

 $hash_ref->{$ltr} = { ten => $count };

你在做

 $hash{a} = { ten => 10 };

毫不奇怪,$hash{a}不再包含零.您必须更改数据结构.您可以使用以下内容:

$hash{a}{value} = 0;
$hash{a}{subhash}{ten} = 10;