Android弹出窗口被解雇

Question

当我单击列表活动中的项目时,我会显示一个弹出窗口.问题是后退键不会关闭它.我尝试在列表活动中捕获后退键但它没有注册它...然后我尝试将onkeylistener注册到我正在传递到弹出窗口的视图中.像这样:

pop.setOnKeyListener(new View.OnKeyListener() {

        @Override
        public boolean onKey(View v, int keyCode, KeyEvent event) {
            // TODO Auto-generated method stub
            boolean res=false;
            if (keyCode == KeyEvent.KEYCODE_BACK && event.getRepeatCount() == 0) {
                // do something on back.
                Log.e("keydown","back");
                if (pw.isShowing()) {
                    Log.e("keydown","pw showing");
                    pw.dismiss();
                    res = true;
                }
            } else {
                res = false;
            }
            return res;
        }
    });

传递给像这样的弹出窗口:

pw = new PopupWindow(
       pop, 
       240, 
       70, 
       true);

但那个听众既不会开火也不会开火.你能帮助我吗？我没有想法:)

Answer 1

这是因为弹出窗口不响应onTouch或onKey事件,除非它的背景为!= null.看看我写的一些代码来帮助解决这个问题.在基本情况下,您可以调用PopupWindow#setBackgroundDrawable(new BitmapDrawable())以强制它按您期望的方式运行.您不需要自己的onKey侦听器.PopupWindow#setOutsideTouchable(true)当用户在窗口边界外单击时,您可能还需要调用它.

扩展的深奥答案:

背景不能为空的原因是因为发生了什么PopupWindow#preparePopup.如果它检测到background != null它创建了一个实例PopupViewContainer并调用setBackgroundDrawable它并将内容视图放入其中.PopupViewContainer基本上是一个FrameLayout侦听触摸事件和KeyEvent.KEYCODE_BACK事件来解雇窗口.如果background == null,则不执行任何操作,只使用您的内容视图.作为替代PopupWindow处理方法的替代方法,您可以扩展根目录ViewGroup以按照您的方式运行.

Answer 2

按照以下方式工作正常:

PopupWindow pw;
LayoutInflater inflater = (LayoutInflater)this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View layout = inflater.inflate(R.layout.weight_popup, (ViewGroup)findViewById(R.id.linlay_weight_popup));
pw = new PopupWindow(layout,LayoutParams.FILL_PARENT,LayoutParams.WRAP_CONTENT, true);
pw.setBackgroundDrawable(new BitmapDrawable());
pw.setOutsideTouchable(true);
pw.showAsDropDown(btnSelectWeight);

Answer 3

对于新项目,最好使用

popupWindow.setBackgroundDrawable(new ColorDrawable());

代替

popupWindow.setBackgroundDrawable(new BitmapDrawable());

不推荐使用BitmapDrawable.此外,在这种情况下,它比ShapeDrawable更好.我注意到当PopupWindow是一个带圆角的矩形时,ShapeDrawable用黑色填充角落.

Answer 4

一个非常简单的解决方案是编写pw.setFocusable(true),但可能你不想这样做,因为MapActivity不会处理触摸事件.

更好的解决方案是覆盖后退键,例如:

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {

    // Override back button
    if (keyCode == KeyEvent.KEYCODE_BACK) {
        if (pw.isShowing()) {
            pw.dismiss();
            return false;
        }
    }
    return super.onKeyDown(keyCode, event);
} 

祝好运!

Answer 5

对于新的搜索者，因为new BitmapDrawablenow( The constructor BitmapDrawable() is deprecated)不允许创建 a ，因此您必须将其更改为 a new ShapeDrawable()，以便您将更改：

pw.setBackgroundDrawable(new BitmapDrawable());

到 ：

pw.setBackgroundDrawable(new ShapeDrawable());

整个工作将是这样的：

PopupWindow pw;
LayoutInflater inflater = (LayoutInflater)this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View layout = inflater.inflate(R.layout.weight_popup, (ViewGroup)findViewById(R.id.linlay_weight_popup));
pw = new PopupWindow(layout,LayoutParams.WRAP_CONTENT,LayoutParams.WRAP_CONTENT, true);
pw.setOutsideTouchable(true);
pw.setBackgroundDrawable(new ShapeDrawable());
pw.setTouchInterceptor(new OnTouchListener() { // or whatever you want
        @Override
        public boolean onTouch(View v, MotionEvent event)
        {
            if(event.getAction() == MotionEvent.ACTION_OUTSIDE) // here I want to close the pw when clicking outside it but at all this is just an example of how it works and you can implement the onTouch() or the onKey() you want
            {
               pw.dismiss();
               return true;
            }
            return false;
        }

});
pw.showAtLocation(layout, Gravity.CENTER, 0, 0);