获取子串忽略数字索引

Question

我有以下两个字符串:

var block = "//div[@class='gd-row browse-grid-row'][1]/div[@class='gd-col gu3'][1]/div"

var full =  "//div[@class='gd-row browse-grid-row'][1]/div[@class='gd-col gu3'][2]/div[@class='product-unit unit-4 browse-product new-design ']/div[@class='pu-details lastUnit']/div[@class='pu-price']/div[@class='pu-border-top']/div[@class='pu-final']/span"

我需要检查块是否是完全忽略所有索引的子串.

基本上我想忽略表单的所有模式:

'[数]'

检查子字符串时.我如何在JavaScript中执行此操作？

Answer 1

使用replace和indexOf:

var regex = regex = /\[\d+\]/g;

full.replace(regex, '').indexOf(block.replace(regex, '')) > -1