拆分后的字符串:和之前？

Question

我有一个像这样的长字符串:

je!tress:e?tu!tress:es?il!tress:e?nous!tress:ons?vous!tress:ez?ils!tress:ent?

我想在之后分割字符串:之前？.所以我想进入数组:

{e,es,e,ons,ez,en}

我知道我可以这样做:

 NSArray *subStrings = [stringToChange componentsSeparatedByString:@":"];

但这还不够.我怎么能这样做呢？任何帮助将不胜感激!

Answer 1

另一种选择是使用NSRegularExpression类。

使用这种模式：

\\:([^\?]+)\?

示例代码：

NSString *sample  = @"je!tress:e?tu!tress:es?il!tress:e?nous!tress:ons?vous!tress:ez?ils!tress:ent?";
NSString *pattern = @"\\:([^\?]+)\?";

NSError *error = NULL;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern
                                                                       options:NSRegularExpressionCaseInsensitive
                                                                         error:&error];


NSArray *matches = [regex matchesInString:sample
                                  options:0
                                    range:NSMakeRange(0, [sample length])];
if(!error && [matches count] > 0) {
    for (NSTextCheckingResult *match in matches) {
        NSRange matchRange = [match range];
        NSLog(@"%@" ,[sample substringWithRange:matchRange]);
    }
}

输出：

2015-07-03 12:16:39.037 TestRegex[3479:48301] :e
2015-07-03 12:16:39.039 TestRegex[3479:48301] :es
2015-07-03 12:16:39.039 TestRegex[3479:48301] :e
2015-07-03 12:16:39.040 TestRegex[3479:48301] :ons
2015-07-03 12:16:39.040 TestRegex[3479:48301] :ez
2015-07-03 12:16:39.040 TestRegex[3479:48301] :ent