Hibernate - OGM [PersistenceUnit:person]无法构建Hibernate SessionFactory

iha*_*pyk 4 java xml hibernate hibernate-ogm

我收到以下错误

线程"main"中的异常javax.persistence.PersistenceException:[PersistenceUnit:person]无法在org.hibernate.jpa的org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.persistenceException(EntityManagerFactoryBuilderImpl.java:1249)中构建Hibernate SessionFactory.在org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl $ 4的org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl $ 4.perform(EntityManagerFactoryBuilderImpl.java:860)中的boot.internal.EntityManagerFactoryBuilderImpl.access $ 600(EntityManagerFactoryBuilderImpl.java:120) .perform(EntityManagerFactoryBuilderImpl.java:850)位于org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java)的org.hibernate.boot.registry.classloading.internal.ClassLoaderServiceImpl.withTccl(ClassLoaderServiceImpl.java:425) :849)org.hibernate.ogm.jpa.Hibe上的org.hibernate.jpa.HibernatePersistenceProvider.createEntityManagerFactory(HibernatePersistenceProvider.java:75)rnateOgmPersistence.createEntityManagerFactory(HibernateOgmPersistence.java:63)位于javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:55)的javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:39)at com.ihappyk.utility.Utility.setUpEntityManagerFactory (utility.java:11)​​com.ihappyk.work.PersonWorker.main(PersonWorker.java:14)引起:org.hibernate.MappingException:无法实例化id生成器[entity-name = com.ihappyk.model.Person ] org.hibernate.id.factory.内部.DefaultIdentifierGeneratorFactory.createIdentifierGenerator(DefaultIdentifierGeneratorFactory.java:123)位于org.hibernate.internal.SessionFactoryImpl的org.hibernate.mapping.SimpleValue.createIdentifierGenerator(SimpleValue.java:225).(SessionFactoryImpl .java:323)org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1859)org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl $ 4.perform(EntityManagerFactoryBuilderImpl.java:857)... 9 m ore造成:org.hibernate.HibernateException:org.hibernate.id.factory.internal中org.hibernate.id.UUIDGenerator.configure(UUIDGenerator.java:111)上UUID转换的意外返回类型[java.lang.Long] .DefaultIdentifierGeneratorFactory.createIdentifierGenerator(DefaultIdentifierGeneratorFactory.java:117)... 13更多

Utilty.java

public class Utility {
    private static EntityManagerFactory entityManagerFactory;

    //@BeforeClass
    public static EntityManagerFactory setUpEntityManagerFactory() {
        entityManagerFactory = Persistence.createEntityManagerFactory( "person" );
        return entityManagerFactory;
    }

    //@AfterClass
    public static void closeEntityManagerFactory() {
        entityManagerFactory.close();
    }
}
Run Code Online (Sandbox Code Playgroud)

持久的阶级

@Entity
public class Person {

        @Id
        @GeneratedValue(generator = "uuid")
        @GenericGenerator(name = "uuid", strategy = "uuid2")
        private long id;

        private String firstName;
        private String lastName;

        public long getId() {
            return id;
        }
        public void setId(long id) {
            this.id = id;
        }
        public String getFirstName() {
            return firstName;
        }
        public void setFirstName(String firstName) {
            this.firstName = firstName;
        }
        public String getLastName() {
            return lastName;
        }
        public void setLastName(String lastName) {
            this.lastName = lastName;
        }

        public Person(){

        }

        public Person(String firstName, String lastName) {
            this.firstName = firstName;
            this.lastName = lastName;
        }    
}
Run Code Online (Sandbox Code Playgroud)

主要班级

public class PersonWorker {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        EntityManagerFactory emf = Utility.setUpEntityManagerFactory();

        EntityManager em = emf.createEntityManager();

        em.getTransaction().begin();

            // create a Person
        Person bob = new Person( "Bob", "McRobb" );

        em.persist( bob );
        em.getTransaction().commit();
        em.close();
        emf.close();

    }

}
Run Code Online (Sandbox Code Playgroud)

persistance.xml

<?xml version="1.0"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
             xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
             version="2.0">

    <persistence-unit name="person" transaction-type="JTA">
        <provider>org.hibernate.ogm.jpa.HibernateOgmPersistence</provider>
       <class>com.ihappyk.model.Person</class>
        <properties>
            <property name="hibernate.ogm.datastore.provider" value="mongodb" />
            <property name="hibernate.ogm.datastore.database" value="hibernateOGM" />
            <property name="hibernate.ogm.datastore.host" value="127.0.0.1" />
            <property name="hibernate.ogm.datastore.port" value="27017" />
            <property name="hibernate.ogm.datastore.provider" value="org.hibernate.ogm.datastore.mongodb.impl.MongoDBDatastoreProvider"/>

            <property name="hibernate.transaction.jta.platform" value="org.hibernate.service.jta.platform.internal.JBossStandAloneJtaPlatform"/>
        </properties>
    </persistence-unit>
</persistence>
Run Code Online (Sandbox Code Playgroud)

Gun*_*nar 8

根异常说明了一切:

Caused by: org.hibernate.HibernateException: Unanticipated return type [java.lang.Long] for UUID
Run Code Online (Sandbox Code Playgroud)

您正在一个它不支持的类型上使用UUID id生成器.您应该使用String而不是Long在这种情况下.