我想在setAdapter()方法后点击一个项目.
考虑一下,如果您已在Activity中声明并初始化了一个Button,那么您可以从该活动的任何范围以编程方式对其执行单击,并且侦听器将起作用.我想要类似的东西,能够点击我的GridView的任何项目.
到目前为止,我已经逐一尝试了以下所有方法,但它们似乎都没有工作,我尝试了不同的堆栈问题但是甚至没有一个答案对我有效.
iconsGrid.setSelection(2);,
iconsGrid.setSelected(true);,
iconsGrid.performClick();,
iconsGrid.performItemClick(iconsGrid, 2, 2);,
iconsGrid.performItemClick(iconsGrid, 2, iconsGrid.getItemIdAtPosition(2));,
//Activity
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
mTextView = (TextView) findViewById(R.id.txt);
Integer[] resource_icons = {
R.drawable.ic_attachment,
R.drawable.ic_attachment,
R.drawable.ic_attachment,
R.drawable.ic_attachment,
R.drawable.ic_attachment,
R.drawable.ic_attachment };
GridView iconsGrid = (GridView) findViewById(R.id.gv_icons);
IconGridAdapter iconAdapter = new IconGridAdapter(this, resource_icons);
iconsGrid.setAdapter(iconAdapter);
/*
* I want to perform a click here
*/
}
//Adapter
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater li;
View grid;
if (convertView == null) {
grid = new View(mContext);
li = ((Activity) mContext).getLayoutInflater();
grid = li.inflate(R.layout.grid_cell_imageview, parent, false);
} else {
grid = (View) convertView;
}
ImageView imageView = (ImageView) grid.findViewById(R.id.image);
imageView.setImageResource(imageId[position]);
return grid;
}
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好吧,让我们这样做
声明你的适配器中的一个字段说
private int selectedPosition=-1;
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现在为此创建一个setter
private void setSelectedPosition(int position)
{
selectedPosition=position;
}
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现在在你的getView方法中
if(position==selectedPosition)
{
grid.setSelected(true);
//OR
grid.setBackgroundColor(<Some Color>);
}
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现在设置适配器后
adapter.setSelectedPosition(<your desired selected item position>);
adapter.notifyDataSetChanged();
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