在MongoDB C#2.0中允许Int32溢出(新驱动程序)

Question

我有一个uint32来序列化到MongoDB.

我曾经能够使用https://jira.mongodb.org/browse/CSHARP-252中的以下代码执行此操作

public class AlwaysAllowUInt32OverflowConvention : ISerializationOptionsConvention
{
    public IBsonSerializationOptions GetSerializationOptions(MemberInfo memberInfo)
    {
        Type type = null;
        var fieldInfo = memberInfo as FieldInfo;
        if (fieldInfo != null)
        {
            type = fieldInfo.FieldType;
        }
        var propertyInfo = memberInfo as PropertyInfo;
        if (propertyInfo != null)
        {
            type = propertyInfo.PropertyType;
        }


        if (type == typeof(uint))
        {
            return new RepresentationSerializationOptions(BsonType.Int32) { AllowOverflow = true };
        }
        else
        {
            return null;
        }
    }
}

然而,在新的MongoDB库ISerializationOptionsConvention和RepresentationSerializationOptions不存在.我已经看过了,看不出如何注册默认的ConventionPack(？)以允许uint32在新库上溢出int32.

如何在不向我的POCO 添加BsonRepresentation属性的情况下执行此操作？

Answer 1

有两种方法我可以想到你可以做到这一点.可能最简单的方法是简单地为类型UInt32注册一个适当配置的序列化器,如下所示:

var uint32Serializer = new UInt32Serializer(BsonType.Int32, new RepresentationConverter(true, true));
BsonSerializer.RegisterSerializer(uint32Serializer);

如果你想使用约定(只有在自动映射类时才适用),你可以这样做:

public class AlwaysAllowUInt32OverflowConvention : IMemberMapConvention
{
    public string Name
    {
        get { return "AlwaysAllowUInt32Overflow"; }
    }

    public void Apply(BsonMemberMap memberMap)
    {
        if (memberMap.MemberType == typeof(UInt32))
        {
            var uint32Serializer = new UInt32Serializer(BsonType.Int32, new RepresentationConverter(true, true));
            memberMap.SetSerializer(uint32Serializer);
        }
    }
}

并注册这样的约定:

var alwaysAllowUInt32OverflowConvention = new AlwaysAllowUInt32OverflowConvention();
var conventionPack = new ConventionPack();
conventionPack.Add(alwaysAllowUInt32OverflowConvention);
ConventionRegistry.Register("AlwaysAllowUInt32Overflow", conventionPack, t => true);