编写以下函数的惯用方式是什么?
(split-first #"." "abc.def.ghi") ;;=>["abc", "def.ghi"]
(split-last #"." "abc.def.ghi") ;;=>["abc.def", "ghi"]
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有一个明显的(丑陋的?)解决方案使用split,但我确信有更优雅的解决方案?也许使用 regexes/indexOf/split-with ?
对于拆分优先,最好的方法是:
(defn split-first [re s]
(clojure.string/split s re 2))
(split-first #"\." "abc.def.ghi")
=> ["abc" "def.ghi"]
(split-first #"<>" "abc<>def<>ghi")
=> ["abc" "def<>ghi"]
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split-last 的一种方法是使用负前瞻断言:
(defn split-last [re s]
(let [pattern (re-pattern (str re "(?!.*" re ")"))]
(split-first pattern s)))
(split-last #"\." "abc.def.ghi")
=> ["abc.def" "ghi"]
(split-last #"<>" "abc<>def<>ghi")
=> ["abc<>def" "ghi"]
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