需要调整此SQL查询以提高性能

She*_*noy 6 sql database oracle query-performance sql-tuning

我有以下查询.由于其中的子查询,这会降低性能.我尝试了很多来添加Join而不是Subquery.但是徒劳无功 任何人都可以告诉我如何使用JOIN重写此查询?

update Table_1
set status = 'Status_2' 
where status ='status_1' and (col_1, col_2, col_3, nvl(col_4,0), col_5) in ( 
               select col_1, col_2, col_3, nvl(col_4,0), col_5 from Table_2 where status ='Status_0');
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请看SELECT * FROM table(DBMS_XPLAN.Display);下面的内容

Plan hash value: 1290346170
------------------------------------------------------------------------------------------------------
| Id  | Operation                     | Name                 | Rows  | Bytes | Cost (%CPU)| Time     |
------------------------------------------------------------------------------------------------------
|   0 | UPDATE STATEMENT              |                      |     1 |   376 |   456   (3)| 00:00:06 |
|   1 |  UPDATE                       | Table_1              |       |       |            |          |
|   2 |   NESTED LOOPS                |                      |       |       |            |          |
|   3 |    NESTED LOOPS               |                      |     1 |   376 |   456   (3)| 00:00:06 |
|   4 |     SORT UNIQUE               |                      |     1 |   316 |   454   (3)| 00:00:06 |
|*  5 |      TABLE ACCESS FULL        | Table_2              |     1 |   316 |   454   (3)| 00:00:06 |
|*  6 |     INDEX RANGE SCAN          | Table1_INDEX         |     1 |       |     1   (0)| 00:00:01 |
|*  7 |    TABLE ACCESS BY INDEX ROWID| Table_1              |     1 |    60 |     1   (0)| 00:00:01 |
------------------------------------------------------------------------------------------------------`enter code here`
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Wer*_*eit 2

当你这样做时,效果会更好吗?

update 
   (select Table_1.status
   from Table_1
      join Table_2 on 
             Table_1.col_1 = Table_2.col_1
         and Table_1.col_2 = Table_2.col_2
         and Table_1.col_3 = Table_2.col_3
         and nvl(Table_1.col_4, 0) = nvl(Table_2.col_4, 0)
         and Table_1.col_5 = Table_2.col_5
   where Table_1.status = 'status_1'
      and Table_2.status = 'Status_0')
set status = 'Status_2' ;
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