Mr.*_*ith 3 c++ image direct2d visual-c++
我正在开发一个需要修改屏幕上已有内容的程序。所以我只有一个ID2D1Bitmap我使用创建的pRenderTarget->CopyFromRenderTarget。
我想做的是将效果应用于该位图。效果只会返回ID2D1Image,但我需要有一个ID2D1Bitmap.
有没有办法做到这一点?
编辑1:
ID2D1Bitmap* myBitmap //the bitmap I want to apply the effect to
ID2D1Effect* effect = NULL;
pDeviceContext->CreateEffect(CLSID_D2D1Saturation, &effect);
effect->SetValue(D2D1_SATURATION_PROP_SATURATION, 0.0f);
effect->SetInput(0, myBitmap);
ID2D1Image* pImg = NULL;
effect->GetOutput(&pImg);
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如果我投射此图像,getPixelSize() 会引发访问冲突。
我解决了。它很脏,但很管用。
ID2D1Bitmap* convertImageToBitmap(ID2D1Image* pImg, D2D1_SIZE_U size)
{
ID2D1Image* oldTarget = NULL;
ID2D1Bitmap1* targetBitmap = NULL;
//Create a Bitmap with "D2D1_BITMAP_OPTIONS_TARGET"
D2D1_BITMAP_PROPERTIES1 bitmapProperties =
D2D1::BitmapProperties1(
D2D1_BITMAP_OPTIONS_TARGET,
D2D1::PixelFormat(DXGI_FORMAT_B8G8R8A8_UNORM, D2D1_ALPHA_MODE_PREMULTIPLIED)
);
pDeviceContext->CreateBitmap(size, 0, 0, bitmapProperties, &targetBitmap);
//Save current Target, replace by ID2D1Bitmap
pDeviceContext->GetTarget(&oldTarget);
pDeviceContext->SetTarget(targetBitmap);
//Draw Image on Target (if currently not drawing also call Begin/EndDraw)
pDeviceContext->DrawImage(pImg);
//Set previous Target
pDeviceContext->SetTarget(oldTarget);
oldTarget->Release();
return targetBitmap;
}
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