Anm*_*ggi 12 python twitter tweepy twitter-streaming-api
我使用以下代码来流式传输我的Twitter帐户收到的邮件 - :
from tweepy import Stream
from tweepy import OAuthHandler
from tweepy import API
from tweepy.streaming import StreamListener
# These values are appropriately filled in the code
consumer_key = ""
consumer_secret = ""
access_token = ""
access_token_secret = ""
class StdOutListener( StreamListener ):
def __init__( self ):
self.tweetCount = 0
def on_connect( self ):
print("Connection established!!")
def on_disconnect( self, notice ):
print("Connection lost!! : ", notice)
def on_data( self, status ):
print("Entered on_data()")
print(status, flush = True)
return True
def on_direct_message( self, status ):
print("Entered on_direct_message()")
try:
print(status, flush = True)
return True
except BaseException as e:
print("Failed on_direct_message()", str(e))
def on_error( self, status ):
print(status)
def main():
try:
auth = OAuthHandler(consumer_key, consumer_secret)
auth.secure = True
auth.set_access_token(access_token, access_token_secret)
api = API(auth)
# If the authentication was successful, you should
# see the name of the account print out
print(api.me().name)
stream = Stream(auth, StdOutListener())
stream.userstream()
except BaseException as e:
print("Error in main()", e)
if __name__ == '__main__':
main()
Run Code Online (Sandbox Code Playgroud)
我可以打印我的名字以及"建立连接!" 信息.
但每当我从朋友的个人资料中向我自己的个人资料发送直接消息时,都不会调用任何方法.
虽然,每当我从我的个人资料中发推文时,它都会被程序正确打印.
我和我的朋友都在Twitter上互相关注,因此直接邮件权限应该没有任何问题.
这样做的正确方法是什么?
此外,如果它根本无法在Tweepy中完成,我准备使用任何其他Python库.
我在Windows 7上使用Tweepy 3.3.0和Python 3.4.
问题中提供的代码确实是正确的.
问题是我在将应用程序权限更改为" 读取,写入和指向消息 " 后忘记重新生成访问令牌和密钥.
注意:直接消息到达on_data()
方法而不是on_direct_message()
方法.