无法将String转换为int,但两者都是字符串？

Question

我只是在一本Java夏季课的书中搞一些练习因为我有点领先,这意味着这不是功课.我收到一条错误消息,指出你无法转换String为int但是两者都是字符串,一个是变量,一个是数组.

就是这条线,我遇到了麻烦...... select = items[select];

public class CarpentryChoice {

    public static void main(String[] args) {
        String items [] = {"Table", "Desk", "Chair", "Couch", "Lazyboy"};
        int price [] = {250, 175, 125, 345, 850};

        String select;

        Scanner scan = new Scanner(System.in);

        System.out.println("Please enter an item to view it's price: ");
        select = scan.nextLine();

        for(int i=0; i < items.length; i++) {
            select = items[select];
        }       
    }
}

Answer 1

因为它select是一个String变量,所以它不能用作数组中的索引.

select = items[select];

我相信你的意思是使用索引值i在for环(其中i是0到items.length).就像是

select = items[i];

但是,根据您的评论,我相信您真的很想要

int select = scan.nextInt();
System.out.println("You selected: " + items[select]);

根据您的编辑,您可以使用两个数组和两个循环.就像是,

String items[] = { "Table", "Desk", "Chair", "Couch", "Lazyboy" };
int price[] = { 250, 175, 125, 345, 850 };
Scanner scan = new Scanner(System.in);
int pos = -1;
outer: while (pos == -1) {
    System.out.println("Please enter an item to view it's price: ");
    String select = scan.nextLine();
    for (int i = 0; i < items.length; i++) {
        if (items[i].equalsIgnoreCase(select.trim())) {
            pos = i;
            break outer;
        }
    }
}
if (pos != -1) {
    System.out.printf("The price is %d%n", price[pos]);
}

但是Map(在我看来)是一个更好的解决方案(它肯定更有效).喜欢,

String[] items = { "Table", "Desk", "Chair", "Couch", "Lazyboy" };
int[] price = { 250, 175, 125, 345, 850 };
Map<String, Integer> map = new HashMap<>();
for (int i = 0; i < items.length; i++) {
    map.put(items[i], price[i]);
}
Scanner scanner = new Scanner(System.in);
System.out.println("Please enter an item to view it's price: ");
while (scanner.hasNextLine()) {
    String item = scanner.nextLine().trim();
    if (map.containsKey(item)) {
        System.out.printf("The price is %d%n", map.get(item));
    }
    System.out.println("Please enter an item to view it's price: ");    
}