匀称:在两个切割点处从线绳上切下一块

Question

众所周知的功能

from shapely.geometry import *
from shapely.wkt import loads

def cut(line, distance):
# Cuts a line in two at a distance from its starting point
if distance <= 0.0 or distance >= line.length:
    return [LineString(line)]
coords = list(line.coords)
for i, p in enumerate(coords):
    pd = line.project(Point(p))
    if pd == distance:
        return [
            LineString(coords[:i+1]),
            LineString(coords[i:])]
    if pd > distance:
        cp = line.interpolate(distance)
        return [
            LineString(coords[:i] + [(cp.x, cp.y)]),
            LineString([(cp.x, cp.y)] + coords[i:])]

将形状上的线串分成两行距离.

我需要做的是在线上的某个位置从线上切下一段长度

示例行:

line = loads("LINESTRING (12.0133696 47.8217147, 12.0132944 47.8216655, 12.0132056 47.8215749, 12.0131542 47.8215034, 12.0130522 47.8212931, 12.0129941 47.8211294, 12.0130381 47.8209553, 12.0131116 47.8208718, 12.013184 47.8208107, 12.0133547 47.8207312, 12.0135537 47.8206727, 12.013915 47.8206019, 12.0141624 47.8205671, 12.0144317 47.8204965)")

我尝试了一种方法来获得一些线条之间的差异,这是通过应用上面的切割功能得到的,但由于形状限制,结果并不好.

有任何想法吗？

Answer 1

我会自己回答,并对改进感到高兴:

def cut_piece(line,distance, lgth):
    """ From a linestring, this cuts a piece of length lgth at distance.
    Needs cut(line,distance) func from above ;-) 
    """
    precut = cut(line,distance)[1]
    result = cut(precut,lgth)[0]
    return result