在SQL中查找并替换所有特殊字符

Question

我想复制新列中的所有行,并用 - 替换所有特殊字符.我的代码如下.

我的桌子设计

 select * from mycode
    UPDATE mycode
    SET newName = Replace(myname, '%[^0-9a-zA-Z]%', '-')

它正在使用我的代码进行复制,但不会替换特殊字符

结果

Answer 1

尝试创建此功能

create function dbo.RemoveSpecialChars (@s varchar(256)) returns varchar(256)
   with schemabinding
begin
   if @s is null
      return null
   declare @s2 varchar(256)
   set @s2 = ''
   declare @l int
   set @l = len(@s)
   declare @p int
   set @p = 1
   while @p <= @l begin
      declare @c int
      set @c = ascii(substring(@s, @p, 1))
      if @c between 48 and 57 or @c between 65 and 90 or @c between 97 and 122
         set @s2 = @s2 + char(@c)
      set @p = @p + 1
      end
   if len(@s2) = 0
      return null
   return @s2
   end

然后做你的 UPDATE

   UPDATE mycode
    SET newName = dbo.RemoveSpecialChars(mycode)

Answer 2

试试这个查询

DECLARE @specialchar varchar(15)
DECLARE @getspecialchar CURSOR
SET @getspecialchar = CURSOR FOR
SELECT DISTINCT poschar 
    FROM   MASTER..spt_values S 
           CROSS APPLY (SELECT SUBSTRING(newName ,NUMBER,1) AS poschar from mycode ) t 
    WHERE  NUMBER > 0 

           AND NOT (ASCII(t.poschar) BETWEEN 65 AND 90 
                     OR ASCII(t.poschar) BETWEEN 97 AND 122 
                     OR ASCII(t.poschar) BETWEEN 48 AND 57)

OPEN @getspecialchar 
FETCH NEXT
FROM @getspecialchar INTO @specialchar 
WHILE @@FETCH_STATUS = 0
BEGIN
    UPDATE mycode 
        SET newName =Replace(myname,@specialchar,'')
FETCH NEXT
FROM @getspecialchar INTO @specialchar 
END
CLOSE @getspecialchar 
DEALLOCATE @getspecialchar