UITextView打开链接

Esq*_*uth 6 uiwebview uitextview datadetectortypes ios swift

我用这个代码:

var textView = UITextView(x: 10, y: 10, width: CardWidth - 20, height: placeholderHeight) //This is my custom initializer
textView.text = "dsfadsaf www.google.com"
textView.selectable = true
textView.dataDetectorTypes = UIDataDetectorTypes.Link
textView.delegate = self
addSubview(textView)
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问题是链接需要长按手势才能打开.我希望它只需点击一下即可打开,就像在Facebook应用程序中一样.

The*_*ist 7

以下示例仅适用于iOS 8+

点击识别器:

let tapRecognizer = UITapGestureRecognizer(target: self, action: Selector("tappedTextView:"))
myTextView.addGestureRecognizer(tapRecognizer)
myTextView.selectable = true
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打回来:

func tappedTextView(tapGesture: UIGestureRecognizer) {

    let textView = tapGesture.view as! UITextView
    let tapLocation = tapGesture.locationInView(textView)
    let textPosition = textView.closestPositionToPoint(tapLocation)
    let attr: NSDictionary = textView.textStylingAtPosition(textPosition, inDirection: UITextStorageDirection.Forward)

    if let url: NSURL = attr[NSLinkAttributeName] as? NSURL {
        UIApplication.sharedApplication().openURL(url)
    }

}
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Swift 3并且没有力量展开:

func tappedTextView(tapGesture: UIGestureRecognizer) {
        guard let textView = tapGesture.view as? UITextView else { return }
        guard let position = textView.closestPosition(to: tapGesture.location(in: textView)) else { return }
        if let url = textView.textStyling(at: position, in: .forward)?[NSLinkAttributeName] as? URL {
            UIApplication.shared.open(url)
        }
    }
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