所以我希望有一个属性getter,它根据不同类型的枚举值返回枚举值,而不必求助于long switch语句.有没有办法使用一个或多个索引来匹配两个枚举列表?
public enum LanguageName
{
Arabic,
Chinese,
Dutch,
English,
Farsi,
French,
Hindi,
Indonesian,
Portuguese,
Spanish,
Urdu
}
public enum LanguageISOCode
{
ara,
zho,
dut,
eng,
fas,
fre,
hin,
ind,
por,
spa,
urd
}
public class language
{
public language()
{
}
public LanguageName Name
{
get
{
// get the Name enum based on the Code enum
}
set;
}
public LanguageISOCode Code
{
get;
set;
}
}
Run Code Online (Sandbox Code Playgroud)
您可以显式声明一个枚举值等于另一个,如下所示:
public enum LanguageName
{
Arabic,
Chinese,
Dutch,
...
}
public enum LanguageISOCode
{
ara = LanguageName.Arabic,
zho = LanguageName.Chinese,
dut = LanguageName.Dutch,
...
}
Run Code Online (Sandbox Code Playgroud)
那将让你在他们之间施放:
LanguageISOCode codeValue = LanguageISOCode.ara;
LanguageName name = (LanguageName)(int)codeValue;
Run Code Online (Sandbox Code Playgroud)
要么
LanguageName nameValue = LanguageName.Arabic;
LanguageISOCode = (LanguageISOCode)(int)nameValue;
Run Code Online (Sandbox Code Playgroud)
虽然以上内容应该回答您的明确问题,但您应该看看该System.Globalization.CultureInfo课程.它为各种文化提供了相当多的功能.