Way*_*2Go 7 java multithreading
我正在尝试编写一个简单的代码来按顺序打印数字.场景就像
Thread Number
T1 1
T2 2
T3 3
T1 4
T2 5
T3 6
T1 7
T2 8
T3 9
...and so on.
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这里是
public class ThreadNumberPrinter {
Object monitor = new Object();
AtomicInteger number = new AtomicInteger(1);
public static void main(String[] args) {
ThreadNumberPrinter tnp = new ThreadNumberPrinter();
Thread t1 = new Thread(tnp.new Printer(1, 3));
Thread t2 = new Thread(tnp.new Printer(2, 3));
Thread t3 = new Thread(tnp.new Printer(3, 3));
t3.start();
t1.start();
t2.start();
}
class Printer implements Runnable {
int threadId;
int numOfThreads;
public Printer(int id, int nubOfThreads) {
threadId = id;
this.numOfThreads = nubOfThreads;
}
public void run() {
print();
}
private void print() {
try {
while (true) {
Thread.sleep(1000l);
synchronized (monitor) {
if (number.get() % numOfThreads != threadId) {
monitor.wait();
} else {
System.out.println("ThreadId [" + threadId
+ "] printing -->"
+ number.getAndIncrement());
monitor.notifyAll();
}
}
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
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但是在第二个线程运行并打印数字2之后,所有线程都进入等待阶段并且没有任何内容被打印出来.我不确定我做错了什么.任何帮助将不胜感激.
public class TestClass {
private volatile Integer count = 1;
private volatile Integer threadIdToRun = 1;
private Object object = new Object();
public static void main(String[] args) {
TestClass testClass = new TestClass();
Thread t1 = new Thread(testClass.new Printer(1));
Thread t2 = new Thread(testClass.new Printer(2));
Thread t3 = new Thread(testClass.new Printer(3));
t1.start();
t2.start();
t3.start();
}
class Printer implements Runnable {
private int threadId;
public Printer(int threadId) {
super();
this.threadId = threadId;
}
@Override
public void run() {
try {
while (count <= 20) {
synchronized (object) {
if (threadId != threadIdToRun) {
object.wait();
} else {
System.out.println("Thread " + threadId + " printed " + count);
count += 1;
if (threadId == 1)
threadIdToRun = 2;
else if (threadId == 2)
threadIdToRun = 3;
else if (threadId == 3)
threadIdToRun = 1;
object.notifyAll();
}
}
}
} catch (Exception e) {
e.printStackTrace();
}
}
}
}
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上面的程序给出输出
Thread 1 printed 1
Thread 2 printed 2
Thread 3 printed 3
Thread 1 printed 4
Thread 2 printed 5
Thread 3 printed 6
Thread 1 printed 7
Thread 2 printed 8
Thread 3 printed 9
Thread 1 printed 10
Thread 2 printed 11
Thread 3 printed 12
Thread 1 printed 13
Thread 2 printed 14
Thread 3 printed 15
Thread 1 printed 16
Thread 2 printed 17
Thread 3 printed 18
Thread 1 printed 19
Thread 2 printed 20
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