luq*_*o33 5 javascript css gulp
这是我设置的Gulp任务.它连接,缩小和重命名一堆css文件.
gulp.task('process-css',function(){
var files = [
'themes/rubbish_taxi/css/bootstrap.css',
'themes/rubbish_taxi/css/custom.css',
'themes/rubbish_taxi/css/responsive.css',
'themes/rubbish_taxi/css/jquery.fancybox.css'
];
return gulp.src(files)
.pipe(sourcemaps.init())
.pipe(concat("main.css"))
.pipe(minifyCSS())
.pipe(rename(function(path) {
path.basename += ".min";
}))
.pipe(sourcemaps.write('sourcemaps/'))
.pipe(gulp.dest('themes/my_theme/css/dist/'));
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});
问题是源文件中存在硬编码的img url(存在css/),因此当我处理这些文件然后将它们输出到子目录(css/dist/)中时,URL会被破坏并且图像不会显示在网站上(404返回).
为了解决这个问题,我如何让Gulp在输出文件中重写img urls?