如何使用Swift 2和XCode 7读取操场文本资源文件

Question

XCode 7 Playground支持游乐场资源.如果我的资源中有GameScene.png,那么当我在我的资源或NSImage(名为:"GameScene.png")中有GameScene.sks时,我可以获得SKScene(fileNamed:"GameScene").

但是如何从Playground资源中读取文本文件？

Answer 1

我们可以使用 Bundle.main

所以,如果你在你的操场上有一个test.json

您可以访问它并打印其内容:

// get the file path for the file "test.json" in the playground bundle
let filePath = Bundle.main.path(forResource:"test", ofType: "json")

// get the contentData
let contentData = FileManager.default.contents(atPath: filePath!)

// get the string
let content = String(data:contentData!, encoding:String.Encoding.utf8)

// print
print("filepath: \(filePath!)")

if let c = content {
    print("content: \n\(c)")
}

会打印

filepath: /var/folders/dm/zg6yp6yj7f58khhtmt8ttfq00000gn/T/com.apple.dt.Xcode.pg/applications/Json-7800-6.app/Contents/Resources/test.json
content: 
{
    "name":"jc",
    "company": {
        "name": "Netscape",
        "city": "Mountain View"
    }
}

Answer 2

Jeremy Chone的答案,更新为Swift 3,Xcode 8:

// get the file path for the file "test.json" in the playground bundle
let filePath = Bundle.main.path(forResource: "test", ofType: "json")

// get the contentData
let contentData = FileManager.default.contents(atPath: filePath!)

// get the string
let content = String(data: contentData!, encoding: .utf8)


// print
print("filepath: \(filePath!)")

if let c = content {
    print("content: \n\(c)")
}

Answer 3

您可以直接使用String和URL.Swift 3中的示例:

let url = Bundle.main.url(forResource: "test", withExtension: "json")!
let text = String(contentsOf: url)

Answer 4

雨燕5

可以Resources通过 Playground 中的捆绑包获取文件夹中的文件。

import UIKit

这里有两种获取 JSON 数据的方法。

小路：

    guard let path = Bundle.main.path(forResource:"test", ofType: "json"),
    let data = FileManager.default.contents(atPath: path) else {
        fatalError("Can not get json data")
    }

网址：

    guard let url = Bundle.main.url(forResource:"test", withExtension: "json") else {
            fatalError("Can not get json file")
    }
    if let data = try? Data(contentsOf: url) {
        // do something with data
    }