TypeError:对象在DJango 1.8 Python 3.4中不是JSON可序列化的

Question

我正在使用DJango 1.8和Python 3.4

当运行以下视图时,Django抛出类型错误 - 对象不是JSON Serializable

Views.py

from django.http import HttpRequest,HttpResponse
from django.http import JsonResponse
from json import dumps

def get_stats(request):
    if request.method == "POST":
        srch_dropV = request.POST['srch_dropAJ']
    else:
        srch_dropV = ''
    if(srch_dropV == 'Green'):
        students = GreenBased.objects.all()
    if(srch_dropV == 'Yellow'):
        students = YellowBased.objects.all()
    response_data = {}
    try:
        response_data['result'] = 'Success'
        response_data['message'] = list(students)
    except:
        response_data['result'] = 'Ouch!'
        response_data['message'] = 'Script has not ran correctly'
    return HttpResponse(JsonResponse(response_data), content_type="application/json")

我正在尝试从mysql数据库中读取几行并将其显示在html文件中,当我正在运行上面的视图时,我正面临下面的错误消息

TypeError: YellowBased: YelloBased object is not JSON serializable

在HTML页面中,我有一个下拉列表..基于所选的选项,我的Ajax会返回从mysql表中获取的记录.

Models.py

class GreenBased(models.Model):
    NumOfStudents = models.CharField(max_length=300,blank=True)
    Green = models.CharField(max_length=300,blank=True)
    class Meta:
        managed = False
        db_table = "GreenStats"

class YelloBased(models.Model):
    NumOfStudents = models.CharField(max_length=300,blank=True)
    Yellow = models.CharField(max_length=300,blank=True)
    class Meta:
        managed = False
        db_table = "YellowStats"

GreenStats和YellowStats表在mysql中只包含2*2行有人可以帮我识别这个问题吗？

Answer 1

你必须序列化你的student对象列表,尝试这样的事情:

from django.http import HttpRequest,HttpResponse
from django.http import JsonResponse
from json import dumps
from django.core import serializers


def get_stats(request):
    if request.method == "POST":
        srch_dropV = request.POST['srch_dropAJ']
    else:
        srch_dropV = ''
    if(srch_dropV == 'Green'):
        students = GreenBased.objects.all()
    if(srch_dropV == 'Yellow'):
        students = YellowBased.objects.all()
    response_data = {}
    try:
        response_data['result'] = 'Success'
        response_data['message'] = serializers.serialize('json', students)
    except:
        response_data['result'] = 'Ouch!'
        response_data['message'] = 'Script has not ran correctly'
    return JsonResponse(response_data)

注意换行:
response_data['message'] = serializers.serialize('json', students)

也是JsonResponse自己的技巧,所以不需要包装它HttpResponse.

检查文档以获得更多自定义:https: //docs.djangoproject.com/en/1.8/topics/serialization/

希望这可以帮助!