使用Uri或资产中的文件创建MediaPlayer时出错

Cal*_*inS 10 android media-player

我将song.mp3复制到我项目的资产目录并编写了这段代码:

private MediaPlayer mp;

Uri uri = Uri.parse("file:///android_asset/song.mp3");

mp=MediaPlayer.create(this, uri);
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运行create语句后,变量mp为null.怎么了?

谢谢.

Red*_*dax 21

试试这个:

try {
    AssetFileDescriptor afd = getAssets().openFd("AudioFile.mp3");
    player = new MediaPlayer();
    player.setDataSource(afd.getFileDescriptor(),afd.getStartOffset(),afd.getLength());
    player.prepare();
    player.start();
    } 
catch (IllegalArgumentException e) {    } 
catch (IllegalStateException e) { } 
catch (IOException e) { } 
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Jer*_*nes 6

试试这个,看看是否有任何异常被捕获:

try {
    MediaPlayer mp = new MediaPlayer();
    mp.setDataSource(this, uri);
}
catch (NullReferenceArgument e) {
    Log.d(TAG, "NullReferenceException: " + e.getMessage());
}
catch (IllegalStateException e) {
    Log.d(TAG, "IllegalStateException: " + e.getMessage());
}
catch (IOException e) {
    Log.d(TAG, "IOException: " + e.getMessage());
}
catch (IllegalArgumentException e) {
    Log.d(TAG, "IllegalArgumentException: " + e.getMessage());
}
catch (SecurityException e) {
    Log.d(TAG, "SecurityException: " + e.getMessage());
}
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捕获的异常将解释您的创建中出现的问题.根据文档,静态创建方法只是上面的try块中的简写.我可以看到的主要区别是静态方法create不会在setDataSource执行时抛出.

  • 我通过修复代码来解决这个问题,以访问资产中的mp3文件.mp = new MediaPlayer(); AssetFileDescriptor afd = getAssets().openFd("song.mp3"); mp.setDataSource(afd.getFileDescriptor()); 谢谢杰尔! (7认同)