Ber*_*ker 8 c# asp.net asp.net-mvc entity-framework razor
我想在一个视图中访问多个模型.我有DAL文件夹和DbContext.
class CvContext : DbContext
{
public CvContext() : base("CvContext")
{
}
public DbSet<LinkModel> Links { get; set; }
public DbSet<AboutModel> Abouts { get; set; }
public DbSet<PortfolioModel> Portfolios { get; set; }
public DbSet<SkillModel> Skills { get; set; }
protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
modelBuilder.Conventions.Remove<PluralizingTableNameConvention>();
}
}
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和HomeController
public class HomeController : Controller
{
private CvContext db = new CvContext();
public ActionResult Index()
{
return View(db.Links.ToList());
}
}
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Index.cshtml
@model IEnumerable<MvcCv.Models.LinkModel>
<ul>
@foreach (var item in Model)
{
<li>
<a href="@Html.DisplayFor(modelItem => item.LinkUrl)">
@Html.DisplayFor(modelItem => item.LinkName)
<span class="icon"></span>
<span class="menu-icon">
<img src="@Url.Content(item.LinkImage)" alt="" />
</span>
</a>
</li>
}
</ul>
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我怎样才能到达所有型号?我会在模型链接中使用foreach for item.谢谢.
hut*_*oid 13
您应该创建一个视图模型,如下所示:
public class FooViewModel
{
public IEnumerable<LinkModel> Links { get; set; }
public IEnumerable<AboutModel> Abouts { get; set; }
public IEnumerable<PortfolioModel> Portfolios { get; set; }
public IEnumerable<SkillModel> Skills { get; set; }
}
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然后从您的控制器填充它们以满足您的要求,例如:
public ActionResult Index()
{
var model = new FooViewModel();
model.Links = db.Links.ToList();
model.Abouts = db.Abouts.ToList();
model.Portfolios = db.Portfolios.ToList();
model.Skills = db.Skills.ToList();
return View(model);
}
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然后在视图中更改模型,FooViewModel
并在那里提供所有属性.
@model FooViewModel
<ul>
@foreach (var item in Model.Links)
{
<li>
@item
</li>
}
</ul>
<ul>
@foreach (var item in Model.Links)
{
<li>
@item
</li>
}
</ul>
// ....etc, obviously change the outputs as needed.
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