将邮件地址解析为联系人的姓名

Tom*_*che 1 android contacts

假设我的地址簿中保存了一个联系人,名为"TomTasche",邮件地址为"stackoverflow@gmail.com".如果我只知道邮件地址,我该如何检索联系人的姓名?

我已经在这里询问了有关检索联系人昵称的类似问题,但如果我更改该代码以查询邮件,那样:

Cursor cur = context.getContentResolver().query(Email.CONTENT_URI, new String[] {Email.DISPLAY_NAME, Email.TYPE, Email.CONTACT_ID}, Email.DATA + " = " + "stackoverflow@gmail.com", null, null);

final int nameIndex = cur.getColumnIndex(Email.DISPLAY_NAME);
final int typeIndex = cur.getColumnIndex(Email.TYPE);
final int idIndex = cur.getColumnIndex(Email.CONTACT_ID);

if (cur.moveToFirst()) {
    name = cur.getString(nameIndex);
    type = cur.getString(typeIndex);
    id = cur.getString(idIndex);
} else {
    name = UNKNOWN;
}
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它强制关闭,logcat告诉我@gmail附近有语法错误.

06-22 09:21:14.260: ERROR/DatabaseUtils(110): Writing exception to parcel
06-22 09:21:14.260: ERROR/DatabaseUtils(110): android.database.sqlite.SQLiteException: near "@gmail": syntax error: , while compiling: SELECT display_name, data2, contact_id FROM view_data_restricted data WHERE (1 AND mimetype = 'vnd.android.cursor.item/phone_v2') AND (data1 = "Tom" <stackoverflow@gmail.com>)
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有趣的是它似乎很好查询.Logcat打印出联系人的姓名:

06-22 09:21:14.260: [...] AND (data1 = "Tom" <stackoverflow@gmail.com>)
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那么,我怎么能找到这个名字呢?

谢谢
汤姆

编辑:

语法错误是由缺少引号引起的,但游标仍然返回null.

Gaw*_*cio 6

使用Phone.DISPLAY_NAME而不是Email.DISPLAY_NAME两个query()getColumnIndex()(前两行).

编辑:

电子邮件查找还有特殊的uri : Email.CONTENT_LOOKUP_URI. 它似乎更方便使用(无需在代码中放置配额或手动编写选择参数):

Uri uri = Uri.withAppendedPath(Email.CONTENT_LOOKUP_URI, Uri.encode("stackoverflow@gmail.com"));
Cursor cur = getContentResolver().query(uri, new String[]{Email.CONTACT_ID, mail.DISPLAY_NAME, Email.TYPE, Phone.DISPLAY_NAME}, null, null, null);
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