在python中提取子字符串

Question

我想解析一个字符串来提取花括号中的所有子串:

'The value of x is {x}, and the list is {y} of len {}'

应该产生:

(x, y)

然后我想格式化字符串以使用值打印初始字符串:

str.format('The value of x is {x}, and the list is {y} of len {}', x, y, len(y))

我怎样才能做到这一点？

Example usage:
def somefunc():
    x = 123
    y = ['a', 'b']
    MyFormat('The value of x is {x}, and the list is {y} of len {}',len(y))

output:
    The value of x is 123, and the list is ['a', 'b'] of len 2

Answer 1

你可以使用string.Formatter.parse:

循环遍历format_string并返回一个可迭代的元组(literal_text,field_name,format_spec,conversion).vformat()使用它将字符串分解为文字文本或替换字段.

元组中的值在概念上表示文字文本的范围,后跟单个替换字段.如果没有文字文本(如果连续出现两个替换字段会发生这种情况),则literal_text将是一个零长度字符串.如果没有替换字段,则field_name,format_spec和conversion的值将为None.

from string import Formatter

s = 'The value of x is {x}, and the list is {y} of len {}'

print([t[1] for t in Formatter().parse(s) if t[1]])
['x', 'y']

不确定这是如何真正帮助您尝试做的,因为您可以在函数中将x和y传递给str.format或使用**locals:

def somefunc():
    x = 123
    y = ['a', 'b']
    print('The value of x is {x}, and the list is {y} of len {}'.format(len(y),**locals()))

如果要打印命名的args,可以添加Formatter输出:

def somefunc():
    x = 123
    y = ['a', 'b']
    print("The named args are {}".format( [t[1] for t in Formatter().parse(s) if t[1]]))
    print('The value of x is {x}, and the list is {y} of len {}'.format(len(y), **locals()))

哪个会输出:

The named args are ['x', 'y']
The value of x is 123, and the list is ['a', 'b'] of len 2