使用PAramiko'放入'SFTP

Question

我安装并编写了以下无法放入文件的Paramiko.它很容易'获取'文件并在其上执行'ls'命令.

#set username & password
username='runaway'
password='runaway'
port=22
source= '/Unzip.sh' 
destination ='/var/mpx/www/http'


#SFTP
client.load_system_host_keys()
print " hostname =%s \n username=%s \n password=%s \n" (hostname,username,password)
t = paramiko.Transport((hostname, port)) 
t.connect(username=username,password=password)
sftp = paramiko.SFTPClient.from_transport(t)
sftp.put(source,destination)
#sftp.close()
#t.close()

使用'put'命令会出现以下错误和堆栈跟踪 -

File "upload_file.py", line 84, in ?
    sftp.put(source,destination)
  File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 522, in put
    fr = self.file(remotepath, 'wb')
  File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 221, in open
    t, msg = self._request(CMD_OPEN, filename, imode, attrblock)
  File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 572, in _request
    return self._read_response(num)
  File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 619, in _read_response
    self._convert_status(msg)
  File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 649, in _convert_status
    raise IOError(text)
IOError: Failure

我该如何克服这个问题？

Answer 1

解决方案对我来说似乎很有趣!

source= '/Unzip.sh' 
destination ='/var/mpx/www/http/Unzip.sh'

刚刚修改了目标路径以包含文件名.没想到像Python这样的一些错误.