Ami*_*Raj -3 uitabbarcontroller uiviewcontroller segue swift xcode6.3

如您所见,屏幕流程如下:
点击"屏幕A"的"按钮2"后,应用程序会在同一个具有标签栏的故事板中显示"屏幕B".点击"屏幕B"的"红色标签"后,应用程序会显示"绿色按钮"(右上角).点击"屏幕B"的"绿色按钮"后,应用程序会显示"故事板2"的"屏幕C".
点击"屏幕C"的后退按钮后,我需要回到"故事板1"的"屏幕B",无论"屏幕C"出现在哪里,"故事板2"的"屏幕C"应该消失从上到下.
是否有可能这样做,如果是,那么如何?
是的,你可以隐藏UIViewController,因为你UIViewController只是正常UIView.
所以只需创建一个@IBOutletfor your UIView和use .hidden方法,如下所示:
@IBOutlet weak var mainview: UIView!
override func viewDidLoad() {
super.viewDidLoad()
mainview.hidden = true
}
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编辑:
正确指定要实现的目标.如果您的显示viewController来自屏幕A或B,直到应该存在某些条件或者ViewController需要一些输入值(字符串,整数等)来处理它并不重要.
Edit2:
参考这个答案如何检查使用了哪个segue
编辑3:
根据你的编辑答案(移动到ScreenC到ScreenB,无论screenC是来自ScreenA还是ScreenB),最好使用三个独立的3个故事板并根据需要调用目标ViewController.
这是ViewController类的代码(移动ScreenA - > ScreenB或ScreenA - > ScreenC)
@IBAction func buttonAisClick(sender: AnyObject) {
// move to ScreenC directly
var moveToNextVC:ViewController3 = self.storyboard?.instantiateViewControllerWithIdentifier("ViewController3") as! ViewController3
self.presentViewController(moveToNextVC, animated: true, completion: nil)
}
@IBAction func ButtomBisClick(sender: AnyObject) {
// move to ScreenB
var moveToNextVC:ViewController2 = self.storyboard?.instantiateViewControllerWithIdentifier("ViewController2") as! ViewController2
self.presentViewController(moveToNextVC, animated: true, completion: nil)
}
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ViewController2类的代码(从ScreenB - > ScreenC移动)
@IBAction func ScreenBbuttonIsClick(sender: AnyObject) {
// move to ScreenC
var moveToNextVC:ViewController3 = self.storyboard?.instantiateViewControllerWithIdentifier("ViewController3") as! ViewController3
self.presentViewController(moveToNextVC, animated: true, completion: nil)
}
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ViewController3类的代码(从ScreenC - > ScreenB移动)
@IBAction func ScreenCbuttonIsclick(sender: AnyObject) {
var moveToNextVC:ViewController2 = self.storyboard?.instantiateViewControllerWithIdentifier("ViewController2") as! ViewController2
self.presentViewController(moveToNextVC, animated: true, completion: nil)
}
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