Dan*_*ann 1 sql-server aggregate-functions sql-server-2008
我有几个查询结果使用一个或多个聚合函数和日期GROUP-BY,所以他们看起来像这样:
Date VisitCount(COUNT) TotalBilling(SUM) 1/1/10 234 15765.21 1/2/10 321 23146.27 1/3/10 289 19436.51
上面简化的SQL是:
SELECT
VisitDate,
COUNT(*) AS VisitCount,
SUM(BilledAmount) AS TotalBilling
FROM Visits
GROUP BY VisitDate
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我想要的是一种将聚合函数(如AVG)应用于结果集中的一列的方法.例如,我想将"AvgVisits"和"AvgBilling"列添加到结果集中,如下所示:
Date VisitCount(COUNT) TotalBilling(SUM) AvgVisits AvgBilling 1/1/10 234 15765.21 281.3 19449.33 1/2/10 321 23146.27 281.3 19449.33 1/3/10 289 19436.51 281.3 19449.33
SQL不允许将聚合函数应用于另一个聚合函数或子查询,因此我能想到的唯一方法是使用临时表或迭代结果集并手动计算值.有没有办法在没有临时表或手动计算的情况下在MSSQL2008中执行此操作?
with cteGrouped as (
SELECT
VisitDate,
COUNT(*) AS VisitCount,
SUM(BilledAmount) AS TotalBilling
FROM Visits
GROUP BY VisitDate),
cteTotal as (
SELECT COUNT(*)/COUNT(DISTINCT VisitDate) as AvgVisits,
SUM(BilledAmount)/COUNT(DISTINCT VisitDate) as AvgBilling
FROM Visits)
SELECT *
FROM cteGrouped
CROSS JOIN cteTotal;
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您可以通过子查询实现相同,我只是发现CTE更具表现力.