Sur*_*h A 9 java data-binding json spring-mvc
我使用以下代码从我的Spring MVC控制器中的android应用程序接收了json数据.
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.bind.annotation.RequestHeader;
@RequestMapping(method = RequestMethod.POST, produces = "application/json")
public @ResponseBody String getMethod(@RequestHeader(value="json") String
headerStr) {
System.out.println("POST");
System.out.println(headerStr);
return "hello";
}
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System.out.println(headerStr)的输出为
{"action":"check_login","password":"test","username":"test"}
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但我想将这个json数据绑定到下面的类.
public class LoginRequest {
private String action;
private String username;
private String password;
public String getAction() {
return action;
}
public void setAction(String action) {
this.action = action;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
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在我的POM.xml中
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>2.5.1</version>
</dependency>
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以下是我的Android代码
HttpParams httpParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParams, 5000);
HttpConnectionParams.setSoTimeout(httpParams, 5000);
HttpClient httpclient = new DefaultHttpClient(httpParams);
HttpPost httppost = new HttpPost( "http://localhost:8080/datarequest");
JSONObject json = new JSONObject();
json.put("action", "check_login");
json.put("username","name");
json.put("password", "password");
JSONArray postjson = new JSONArray();
postjson.put(json);
httppost.setHeader("json", json.toString());
httppost.getParams().setParameter("jsonpost", postjson);
System.out.println(postjson);
HttpResponse response = httpclient.execute(httppost);
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如何解决这个问题呢?
您应该将方法中的参数更改为
public @ResponseBody String getMethod(@RequestBody LoginRequest loginRequest)
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这样,LoginRequest
类将被实例化并绑定到json值,其中键与属性匹配
此外,请确保将json作为正文的一部分发送,添加以下内容
StringEntity se = new StringEntity(json.toString(), "UTF8");
se.setHeader("Content-type", "application/json");
post.setEntity(se);
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该前HttpResponse response = httpclient.execute(httppost);
行
使用杰克逊对象映射器:
ObjectMapper mapper = new ObjectMapper();
LoginRequest login = mapper.readValue(headerStr, LoginRequest.class);
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