如何在Python中交错字符串?
特定
s1 = 'abc'
s2 = 'xyz'
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我怎么得到axbycz?
Joh*_*ooy 15
这是一种方法
>>> s1 = "abc"
>>> s2 = "xyz"
>>> "".join(i for j in zip(s1, s2) for i in j)
'axbycz'
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它也适用于超过2个字符串
>>> s3 = "123"
>>> "".join(i for j in zip(s1, s2, s3) for i in j)
'ax1by2cz3'
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这是另一种方式
>>> "".join("".join(i) for i in zip(s1,s2,s3))
'ax1by2cz3'
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而另一个
>>> from itertools import chain
>>> "".join(chain(*zip(s1, s2, s3)))
'ax1by2cz3'
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一个没有 zip
>>> b = bytearray(6)
>>> b[::2] = "abc"
>>> b[1::2] = "xyz"
>>> str(b)
'axbycz'
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而且效率低下
>>> ((s1 + " " + s2) * len(s1))[::len(s1) + 1]
'axbycz'
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