使用httplib使用python上传文件

Question

conn = httplib.HTTPConnection("www.encodable.com/uploaddemo/")
conn.request("POST", path, chunk, headers)

以上是我想要上传图片的网站"www.encodable.com/uploaddemo/".

我更精通,php所以我无法理解路径和标题的含义.在上面的代码中,chunk是一个由我的图像文件组成的对象.以下代码产生错误,因为我试图在不了解标头和路径的情况下实现.

import httplib

def upload_image_to_url():

    filename = '//home//harshit//Desktop//h1.jpg'
    f = open(filename, "rb")
    chunk = f.read()
    f.close()

    headers = {
        "Content?type": "application/octet?stream",
        "Accept": "text/plain"
    }

    conn = httplib.HTTPConnection("www.encodable.com/uploaddemo/")
    conn.request("POST", "/uploaddemo/files/", chunk)

    response = conn.getresponse()
    remote_file = response.read()
    conn.close()
    print remote_file

upload_image_to_url()

Answer 1

目前,您没有使用先前在代码中声明的标头.您应该将它们作为第四个参数提供给conn.request:

conn.request("POST", "/uploaddemo/files/", chunk, headers)

另外,请注意:您可以open("h1.jpg", "rb")直接进入,conn.request而无需chunk先将其完全读入. conn.request接受类似文件的对象,一次一点地传输文件会更有效:

conn.request("POST", "/uploaddemo/files/", open("h1.jpg", "rb"), headers)