当spring-security收到空凭据(用户名和密码)时,如何创建自定义响应?

TuG*_*llo 11 security spring spring-security basic-authentication postman

我正在使用邮递员向我的服务器发送没有值的用户名和密码; 就像username=nullpassword=null.

在此输入图像描述

为了控制我的服务器的安全性,我使用spring security 3.2.当它收到这些凭证时,spring-security会响应此错误.

Estado HTTP 500 - Fields must not be empty

java.lang.IllegalArgumentException: Cannot pass null or empty values to constructor
    org.springframework.security.core.userdetails.User.<init>(User.java:99)
    org.springframework.security.core.userdetails.User.<init>(User.java:69)
    com.equifax.product.fraud.applicationprocessing.web.rest.interceptors.security.SecurityAuthenticationProvider.retrieveUser(SecurityAuthenticationProvider.java:59)
    org.springframework.security.authentication.dao.AbstractUserDetailsAuthenticationProvider.authenticate(AbstractUserDetailsAuthenticationProvider.java:132)
    org.springframework.security.authentication.ProviderManager.authenticate(ProviderManager.java:156)
    org.springframework.security.authentication.ProviderManager.authenticate(ProviderManager.java:177)
    org.springframework.security.web.authentication.www.BasicAuthenticationFilter.doFilter(BasicAuthenticationFilter.java:168)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.context.request.async.WebAsyncManagerIntegrationFilter.doFilterInternal(WebAsyncManagerIntegrationFilter.java:50)
    org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:107)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.context.SecurityContextPersistenceFilter.doFilter(SecurityContextPersistenceFilter.java:87)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.FilterChainProxy.doFilterInternal(FilterChainProxy.java:192)
    org.springframework.security.web.FilterChainProxy.doFilter(FilterChainProxy.java:160)
    org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:344)
        org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:261)
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我想输出带有错误的自定义消息的JSON,我该怎么做?

这是我的security.xml:

    <security:http create-session="never" use-expressions="true"
    auto-config="false">

    <security:intercept-url pattern="/application/**"
        access="isFullyAuthenticated()" />
    <security:anonymous />
    <security:http-basic entry-point-ref="securityAccessDeniedEntryPoint" />
    <security:access-denied-handler ref="securityAccessDeniedHandler" />
</security:http>

<security:authentication-manager alias="authenticationManager"
    erase-credentials="false">
    <security:authentication-provider
        ref="genericSecurityAuthenticationProvider" />
</security:authentication-manager>
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我使用的是Spring 3.2

小智 3

使用Spring Security的标准异常,如果你已经有一个异常处理程序将消息转换为Json响应,它将自行处理。

        catch (Exception exception)
        {
            throw new AuthenticationCredentialsNotFoundException("Fields must not be empty", exception);
        }
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