如何用坐标移动标记100米

Question

我有2个坐标.坐标1是"人".坐标2是目的地.

如何将坐标1 100米移近坐标2？

这将用于cron作业,因此只包含php和mysql.

例如:

人是:51.26667,3.4454

目的地是:51.575001,4.83889

我如何计算人物的新坐标距离100米？

Answer 1

使用Haversine计算两点之间的差值(以米为单位); 然后按比例调整人物坐标的值.

$radius = 6378100; // radius of earth in meters
$latDist = $lat - $lat2;
$lngDist = $lng - $lng2;
$latDistRad = deg2rad($latDist);
$lngDistRad = deg2rad($lngDist);
$sinLatD = sin($latDistRad);
$sinLngD = sin($lngDistRad);
$cosLat1 = cos(deg2rad($lat));
$cosLat2 = cos(deg2rad($lat2));
$a = ($sinLatD/2)*($sinLatD/2) + $cosLat1*$cosLat2*($sinLngD/2)*($sinLngD/2);
if($a<0) $a = -1*$a;
$c = 2*atan2(sqrt($a), sqrt(1-$a));
$distance = $radius*$c;

喂养你的价值观:

$lat = 51.26667;        //  Just South of Aardenburg in Belgium
$lng = 3.45417;
$lat2 = 51.575001;      //  To the East of Breda in Holland
$lng2 = 4.83889;

结果为102059.82251083米,102.06公里

要调整的比率是100/102059.82251083 = 0.0009798174985988102859004569070625

$newLat = $lat + (($lat2 - $lat) * $ratio);
$newLng = $lng + (($lng2 - $lng) * $ratio);

给出新的纬度51.266972108109和经度3.4555267728867