java中的MultiValueMap

Question

我正在研究带有多个参数的Hashmap(1个键,2个值),我能够找到apache multiValueMap来解决我的问题.

这是我的multiValueMap代码.

import java.util.Set;
import org.apache.commons.collections.map.MultiValueMap;
import org.apache.commons.collections.MultiMap;

public class multiValueMap {

public static void main(String args[]) {
   String a, b, c;
   MultiMap mMap = new MultiValueMap();

   mMap.put("a", "Hello there, It's a wonderful day");
   mMap.put("a", "nice to meet you");

   Set<String> keys = mMap.keySet();

   for (String key : keys) {
      System.out.println("Key = " + key);
      System.out.println("Values = " + mMap.get(key));
      a = String.valueOf(mMap.get(key));

      System.out.println("A : " + a);
    }
 }
}
// The result as below
 Key = a 
 Value = [Hello there, It's a wonderful day, nice to meet you]
 A : [Hello there, It's a wonderful day, nice to meet you]

这是我的问题, 如何为字符串b存储第一个值,为c存储第二个值？ 如果我将MultiMap值的子字符串依赖于","那么它只存储Hello.请给我你的建议.

Answer 1

您可以尝试以下方法:

String a, b, c;

MultiMap mMap = new MultiValueMap();
mMap.put("a", "Hello there, It's a wonderful day");
mMap.put("a", "nice to meet you");

Set<String> keys = mMap.keySet();

for (String key : keys) {
    System.out.println("Key = " + key);
    System.out.println("Values = " + mMap.get(key));
    List<String> list = (List<String>) mMap.get(key);

    b = list.get(0);
    c = list.get(1);
    System.out.println("B : " + b);
    System.out.println("C : " + c);
}