如何根据值从哈希中删除重复的条目

Question

我有一个重复条目的列表.我需要一个基于unit_id的唯一条目列表.

hash_list = {
  "a"=>{"unit_id"=>"43", "dep_id"=>"153", "_destroy"=>"false"},
  "b"=>{"unit_id"=>"43", "dep_id"=>"153", "_destroy"=>"false"},
  "c"=>{"unit_id"=>"43", "dep_id"=>"154", "_destroy"=>"false"},
  "d"=>{"unit_id"=>"42", "dep_id"=>"154", "_destroy"=>"false"}
}

预期产出:

hash_list = {
  "a"=>{"unit_id"=>"43", "dep_id"=>"153", "_destroy"=>"false"},
  "d"=>{"unit_id"=>"42", "dep_id"=>"154", "_destroy"=>"false"}
}

Answer 1

hash_list.to_a
         .uniq! { |_, v| v['unit_id'] }
         .to_h

但请注意,仅基于密钥删除重复项unit_id.
要基于多个键,

hash_list.to_a
         .uniq! { |_, v| v.values_at('unit_id','_destroy') }
         .to_h

请看看Hash#values_at

产量

>> hash_list = { "a"=>{"unit_id"=>"43", "dep_id"=>"153", "_destroy"=>"false"}, "b"=>{"unit_id"=>"43", "dep_id"=>"153", "_destroy"=>"1"}, "c"=>{"unit_id"=>"43", "dep_id"=>"154", "_destroy"=>"false"}, "d"=>{"unit_id"=>"42", "dep_id"=>"154", "_destroy"=>"false"} }
#=> {"a"=>{"unit_id"=>"43", "dep_id"=>"153", "_destroy"=>"false"}, "b"=>{"unit_id"=>"43", "dep_id"=>"153", "_destroy"=>"1"}, "c"=>{"unit_id"=>"43", "dep_id"=>"154", "_destroy"=>"false"}, "d"=>{"unit_id"=>"42", "dep_id"=>"154", "_destroy"=>"false"}}
>> hash_list.to_a.uniq! { |_, v| v.values_at('unit_id','_destroy') }.to_h
#=> {"a"=>{"unit_id"=>"43", "dep_id"=>"153", "_destroy"=>"false"}, "b"=>{"unit_id"=>"43", "dep_id"=>"153", "_destroy"=>"1"}, "d"=>{"unit_id"=>"42", "dep_id"=>"154", "_destroy"=>"false"}}