如何在视图中获得子精灵的位置

Question

我试图根据这里和这个的答案在视图中获得子精灵的位置

for child in platformGroupNode.children {
    CGPoint p = [child.superview convertPoint:child.center toNode:self.view ]
    println(p)
}

但是我不确定如何与SKSpriteNode孩子和SKNode父母一起使用。

我也没有运气尝试过

for child in platformGroupNode.children {
    var pos = child.position
    var viewPos = convertPoint(pos, toNode: self.parent!)
    if viewPos.x < 0 {
        println("Out of screen")
    }
}

Answer 1

您快到了，需要使用的是：

let positionInScene = self.convertPoint(child.position, fromNode: platformGroupNode)
// self in this case is your SKScene, you don't need self here but, IMO, it 
// makes it easier to understand what's converting what.

或等效的将是：

let positionInScene = platformGroupNode.convertPoint(child.position, toNode: self)