在将CamelCase转换为带空格的字符串时忽略现有空格

Question

我想分开camelCase或PascalCase单词空格分开单词集合.

到目前为止,我有:

Regex.Replace(value, @"(\B[A-Z]+?(?=[A-Z][^A-Z])|\B[A-Z]+?(?=[^A-Z]))", " $0", RegexOptions.Compiled);

它适用于将"TestWord"转换为"Test Word"并保持单个单词不变,例如Testing遗留Testing.

然而,ABCTest转换到A B C Test我想要的时候ABC Test.

Answer 1

尝试：

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[A-Z][a-z]+|[A-Z]+(?=[A-Z][a-z])|[a-z]+|[A-Z]+\n

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Regex101 上的示例

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在CS中如何使用？

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string strText = " TestWord asdfDasdf  ABCDef";\n        \nstring[] matches = Regex.Matches(strText, @"[A-Z][a-z]+|[A-Z]+(?=[A-Z][a-z])|[a-z]+|[A-Z]+")\n                .Cast<Match>()\n                .Select(m => m.Value)\n                .ToArray();\n            \nstring result = String.Join(" ", matches);\n

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result=\'Test Word asdf Dasdf ABC Def\'

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怎么运行的

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在示例字符串中：

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[A-Z][a-z]+|[A-Z]+(?=[A-Z][a-z])|[a-z]+|[A-Z]+\n

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[A-Z][a-z]+火柴：

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• [0-4] Test
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• [4-8] Word
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• [13-18]Dasdf
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• [22-26]Test
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• [27-34]Testing
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• [45-50]Camel
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• [50-54]Case
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• [68-73]Aasdf
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• [74-76]Aa
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• [76-79]Bbb
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[A-Z]+(?=[A-Z][a-z])火柴：

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• [19-22]ABC
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[a-z]+火柴：

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• [9-13] qwer
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• [64-68] asdf
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[A-Z]+火柴：

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• [79-81] CD
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