使用jasmine Spies监视服务方法调用

Question

我有以下控制器ViewMeetingCtrl.js

(function () {
    'use strict';
    angular.module('MyApp').controller('ViewMeetingCtrl', ViewMeetingCtrl);

    ViewMeetingCtrl.$inject = ['$scope', '$state', '$http', '$translate', 'notificationService', 'meetingService', '$modal', 'meeting', 'attachmentService'];

    function ViewMeetingCtrl($scope, $state, $http, $translate, notificationService, meetingService, $modal, meeting, attachmentService) {
        $scope.meeting = meeting; 

        $scope.cancelMeeting = cancelMeeting;

        function cancelMeeting(meetingId, companyId) {
            meetingService.sendCancelNotices(companyId, meetingId)
                .success(function () {
                    $state.go('company.view');
                });
        }      
    }
})();

我能够成功地调用spyOn for cancelMeeting(),但不能调用sendCancelNotices方法.我想要做的是,我想测试,只要cancelMeeting()被调用,它调用sendCancelNotices()方法.我知道我应该使用createSpy方法来执行此操作.但我不知道该怎么做.

下面是测试用例ViewMeetingCtrlSpec.js

describe('ViewMeetingCtrl CreateSpy --> Spying --> cancelMeeting', function () {
        var $rootScope, scope, $controller , $q  ;


        var sendCancelNoticesSpy = jasmine.createSpy('sendCancelNoticesSpy');


        beforeEach(angular.mock.module('MyApp'));

        beforeEach(inject(function ($rootScope, $controller ) {
            scope = $rootScope.$new();
            createController = function() {
                return $controller('ViewMeetingCtrl', {
                $scope: scope,
                meeting : {}
                }); 
            };
            var controller = new createController();
        }));

        it("tracks that the cancelMeeting spy was called", function() {
            //some assertion
        });

});

Answer 1

describe('ViewMeetingCtrl', function () {

    var scope, meetingService;

    beforeEach(angular.mock.module('MyApp'));

    beforeEach(inject(function ($rootScope, $controller, _meetingService_) {
        scope = $rootScope.$new();
        meetingService = _meetingService_;
        $controller('ViewMeetingCtrl', {
            $scope: scope,
            meeting : {}
        }); 
    }));

    it('should send cancel notices whan cancelMeeting is called', function() {
        var fakeHttpPromise = {
            success: function() {}
        };
        spyOn(meetingService, 'sendCancelNotices').andReturn(fakeHttpPromise);

        scope.cancelMeeting('foo', 'bar');

        expect(meetingService.sendCancelNotices).toHaveBeenCalledWith('bar', 'foo');
    });

});

我鼓励你停止依赖从服务返回的HTTP承诺.相反,只需考虑服务返回一个承诺.这些更易于模拟,并且当您不再返回HTTP承诺时,不会强制您重写控制器代码.

在你的控制器中:

    function cancelMeeting(meetingId, companyId) {
        meetingService.sendCancelNotices(companyId, meetingId)
            .then(function () {
                $state.go('company.view');
            });
    } 

在你的测试中:

        var fakePromise = $q.when();
        spyOn(meetingService, 'sendCancelNotices')and.returnValue(fakePromise);

        scope.cancelMeeting('foo', 'bar');
        expect(meetingService.sendCancelNotices).toHaveBeenCalledWith('bar', 'foo');