批量生成随机字符串

Question

我试图批量制作一个随机字符串,我不知道该怎么做.我使用%random%函数调用了一个随机数字串,但我不知道如何永久替换变量中的某些字符:

@echo off
set subkey1=%random%%random%%random%%random%%random%%random%
set subkey2=%random%%random%%random%%random%%random%%random%
set subkey3=%random%%random%%random%%random%%random%%random%


ECHO %subkey1:0=a%
ECHO %subkey1:1=b%
ECHO %subkey1:2=c%
ECHO %subkey1:3=d%
ECHO %subkey1:4=e%
ECHO %subkey1:5=f%
ECHO %subkey1:6=g%
ECHO %subkey1:7=h%
ECHO %subkey1:8=i%
ECHO %subkey1:9=j%

ECHO %subkey2:0=k%
ECHO %subkey2:1=l%
ECHO %subkey2:2=m%
ECHO %subkey2:3=n%
ECHO %subkey2:4=o%
ECHO %subkey2:5=p%
ECHO %subkey2:6=q%
ECHO %subkey2:7=r%
ECHO %subkey2:8=s%
ECHO %subkey2:9=t%

ECHO %subkey3:0=u%
ECHO %subkey3:1=v%
ECHO %subkey3:2=w%
ECHO %subkey3:3=x%
ECHO %subkey3:4=y%
ECHO %subkey3:5=z%
REM after going through all the letters, we just pick random ones
ECHO %subkey3:6=a%
ECHO %subkey3:7=g%
ECHO %subkey3:8=k%
ECHO %subkey3:9=o%

set key=%subkey1%%subkey2%%subkey3%
echo String: %key%
pause

所以你可以看到,我能够ECHO不同的键,但我想将新的键保存到变量(子键1中的EX,我想用a替换所有的0,然后保存,如果我查看我的变量之后,我可以看到新的,并能够在不同的功能中调用它.

Answer 1

相同的效果,代码少得多:

@echo off
setlocal enabledelayedexpansion
set "string=abcdefghijklmnopqrstuvwxyz"
set "result="
for /L %%i in (1,1,30) do call :add
echo %result%
goto :eof

:add
set /a x=%random% %% 26 
set result=%result%!string:~%x%,1!
goto :eof

Answer 2

要为变量分配值，请使用 SET 命令：

SET subkey1=%random%%random%%random%%random%%random%%random%

SET subkey1=%subkey1:0=a%
SET subkey1=%subkey1:1=b%
SET subkey1=%subkey1:2=c%
.
.
.
ECHO %subkey1%

当然，请注意，%random%永远不应该将其用作加密目的的来源。