svh*_*985 5 ios core-motion swift
我目前正在构建我的第一个iOS Swift应用程序,使用此应用程序我想在应用程序在后台运行时执行操作.
一旦用户在设备上点击两次,就需要执行该操作.
我启用了后台模式:应用功能中的位置更新
并在AppDelegate中设置AccelerometerUpdatesToQueue函数:
let manager = CMMotionManager()
func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
// Override point for customization after application launch.
if manager.accelerometerAvailable {
manager.accelerometerUpdateInterval = 0.01
manager.startAccelerometerUpdatesToQueue(NSOperationQueue.mainQueue()) {
[weak self] (data: CMAccelerometerData!, error: NSError!) in
println(data.acceleration.z)
}
}
return true
}
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控制台按预期打印出acceleration.z值,但是一旦按下主页按钮,控制台就会打印停止.
我在网上搜索了一个关于如何做到这一点的示例代码,我知道这是可能的...因为我们都知道应用程序"Knock Knock to unlock",但我似乎无法找到一段示例代码对斯威夫特来说.
我得到了它的工作!这是我的解决方案,随意提出改进:)
class AppDelegate: UIResponder, UIApplicationDelegate {
var window: UIWindow?
let manager = CMMotionManager()
var knocked : Bool = false
let motionUpdateInterval : Double = 0.05
var knockReset : Double = 2.0
func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
if manager.deviceMotionAvailable {
manager.deviceMotionUpdateInterval = motionUpdateInterval // seconds
manager.startDeviceMotionUpdatesToQueue(NSOperationQueue.mainQueue()) {
[weak self] (data: CMDeviceMotion!, error: NSError!) in
if (data.userAcceleration.z < -0.7) || (data.userAcceleration.z > 0.7) { // Check if device is knocked
// Check for double knock
if self!.knocked == false {
// First knock
println("First Knock")
self!.knocked = true
}else{
// Second knock
println("Double Knocked")
self!.knocked = false
self!.knockReset = 2.0
// Action:
}
}
// Countdown for reset action (second knock must be within the knockReset limit)
if (self!.knocked) && (self!.knockReset >= 0.0) {
self!.knockReset = self!.knockReset - self!.motionUpdateInterval
}else if self!.knocked == true {
self!.knocked = false
self!.knockReset = 2.0
println("Reset")
}
}
}
return true
}
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