如何通过popViewControllerAnimated为Swift发回数据？

Question

我需要通过popView将一些数据从secondView发送回First View.我如何通过popViewControllerAnimated发回数据？

谢谢!

Answer 1

您可以使用返回数据 delegate

1. 创建protocol于ChildViewController
2. 在中创建delegate变量ChildViewController
3. 扩展ChildViewController协议MainViewController
4. ChildViewController提供MainViewController何时参考navigate
5. 定义delegate方法MainViewController
6. 然后你可以调用delegate方法ChildViewController

例

在ChildViewController中:写下面的代码......

protocol ChildViewControllerDelegate
{
     func childViewControllerResponse(parameter)
}

class ChildViewController:UIViewController
{
    var delegate: ChildViewControllerDelegate?
    ....
}

在MainViewController中

// extend `delegate`
class MainViewController:UIViewController,ChildViewControllerDelegate
{
    // Define Delegate Method
    func childViewControllerResponse(parameter)
    {
       .... // self.parameter = parameter
    }
}

有两种选择:

A)与Segue

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?)
{
   let goNext = segue.destinationViewController as ChildViewController
   goNext.delegate = self
}

B)没有塞格

let goNext = storyboard?.instantiateViewControllerWithIdentifier("childView") as ChildViewController
goNext.delegate = self
self.navigationController?.pushViewController(goNext, animated: true)

方法调用

self.delegate?.childViewControllerResponse(parameter)

Answer 2

如果你想通过弹出发送数据,你可以这样做:

func goToFirstViewController() {
  let a = self.navigationController.viewControllers[0] as A
  a.data = "data"
  self.navigationController.popToRootViewControllerAnimated(true)
}