And*_*eda 2 sql database oracle join
我的db ITEM_MASTER,PRICE_MASTER,COMP_MASTER中有三个表
ITEM_MASTER
STORE_CODE ITEM_CODE ITEM_DESC
011 914004 desccc
PRICE_MASTER
STORE_CODE ITEM_CODE COMP_CODE
011 914004 01
011 914004 02
011 914004 03
011 914004 04
COMP_MASTER
COMP_CODE COMP_DESC STORE_CODE
01 comp1 011
02 comp2 011
03 comp3 011
04 comp4 011
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我想在单个查询中获取所有这些ITEM_CODE
STORE_CODE ITEM_CODE ITEM_DESC COMP_DESC1 COMP_DESC2 COMP_DESC3 COMP_DESC4
011 914004 desccc comp1 comp2 comp3 comp4
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我怎么能为此编写一个oracle SQL查询?
获取此输出涉及两个步骤:连接和枢轴.
一个例子:
首先创建样本表:
SQL> create table item_master (store_code,item_code,item_desc)
2 as
3 select '011', 914004, 'desccc' from dual
4 /
Table created.
SQL> create table price_master (store_code,item_code,comp_code)
2 as
3 select '011', 914004, '01' from dual union all
4 select '011', 914004, '02' from dual union all
5 select '011', 914004, '03' from dual union all
6 select '011', 914004, '04' from dual
7 /
Table created.
SQL> create table comp_master (comp_code,comp_desc,store_code)
2 as
3 select '01', 'comp1', '011' from dual union all
4 select '02', 'comp2', '011' from dual union all
5 select '03', 'comp3', '011' from dual union all
6 select '04', 'comp4', '011' from dual
7 /
Table created.
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第一步是加入.这里我使用ANSI连接语法,但您也可以使用旧的Oracle连接语法.
SQL> select i.store_code
2 , i.item_code
3 , i.item_desc
4 , c.comp_desc
5 from item_master i
6 inner join price_master p
7 on ( i.store_code = p.store_code
8 and i.item_code = p.item_code
9 )
10 inner join comp_master c
11 on ( p.store_code = c.store_code
12 and p.comp_code = c.comp_code
13 )
14 /
STO ITEM_CODE ITEM_D COMP_
--- ---------- ------ -----
011 914004 desccc comp1
011 914004 desccc comp2
011 914004 desccc comp3
011 914004 desccc comp4
4 rows selected.
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comp描述显示在彼此之下,但您希望它们彼此相邻.为此,您可以旋转结果集.请注意,您必须硬编码要转动的行数:
SQL> with t as
2 ( select i.store_code
3 , i.item_code
4 , i.item_desc
5 , c.comp_desc
6 , row_number() over (partition by i.store_code,i.item_code order by c.comp_code) rn
7 from item_master i
8 inner join price_master p
9 on ( i.store_code = p.store_code
10 and i.item_code = p.item_code
11 )
12 inner join comp_master c
13 on ( p.store_code = c.store_code
14 and p.comp_code = c.comp_code
15 )
16 )
17 select store_code
18 , item_code
19 , item_desc
20 , max(decode(rn,1,comp_desc)) comp_desc1
21 , max(decode(rn,2,comp_desc)) comp_desc2
22 , max(decode(rn,3,comp_desc)) comp_desc3
23 , max(decode(rn,4,comp_desc)) comp_desc4
24 from t
25 group by store_code
26 , item_code
27 , item_desc
28 /
STO ITEM_CODE ITEM_D COMP_ COMP_ COMP_ COMP_
--- ---------- ------ ----- ----- ----- -----
011 914004 desccc comp1 comp2 comp3 comp4
1 row selected.
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希望这可以帮助.
问候,Rob.